Chapter 5, Problem 5G.4E

(a)

Interpretation Introduction

Interpretation:

The expression for the equilibrium constant for the given reaction has to be written.

  ${\text{Br}}_{\text{2}\left(\text{g}\right)}\text{+}\text{3}{\text{F}}_{\text{2}\left(\text{g}\right)}\rightleftharpoons \text{2}{\text{BrF}}_{\text{3}\left(\text{g}\right)}$

Concept Introduction:

The equilibrium constant, $\text{K}$, is characteristic of the composition of reaction mixture at equilibrium at a given temperature irrespective of the initial composition of reaction mixture.

For the reaction,

  $\text{a}{\text{A}}_{\left(\text{g}\right)}\text{+}\text{b}{\text{B}}_{\left(\text{g}\right)}\rightleftharpoons \text{c}{\text{C}}_{\left(\text{g}\right)}\text{+}\text{d}{\text{D}}_{\left(\text{g}\right)}$

The equilibrium constant can be written as

  $\text{K}\text{=}\frac{{\left({\text{P}}_{\text{C}}\right)}^{\text{c}}{\left({\text{P}}_{\text{D}}\right)}^{\text{d}}}{{\left({\text{P}}_{\text{A}}\right)}^{\text{a}}{\left({\text{P}}_{\text{B}}\right)}^{\text{b}}}$

(b)

Interpretation Introduction

Interpretation:

The expression for the equilibrium constant for the given reaction has to be written.

  $\text{4}{\text{NH}}_{\text{3}}{}_{\left(\text{g}\right)}\text{+}\text{3}{\text{O}}_{\text{2}\left(\text{g}\right)}\rightleftharpoons \text{2}{\text{N}}_{\text{2}\left(\text{g}\right)}\text{+}\text{6}{\text{H}}_{\text{2}}{\text{O}}_{\left(\text{g}\right)}$

Concept Introduction:

Refer to sub-part (a).