Explanation The required reaction is given below. N 2 ( g ) + 3 H 2 ( g ) ⇌ 2 N H 3 ( g ) , K = 0.036 The expression for equilibrium constant for the above reaction can be written as shown below, K = ( P N H 3 ) 2 ( P N 2 ) ( P H 2 ) 3 Given that, the initial partial pressures of N 2 a n d H 2 are 1.42 b a r a n d 2.87 b a r respectively. An equilibrium table can be set up as given below. C o m p o s i t i o n ( b a r ) N 2 H 2 N H 3 I n i t i a l p r e s s u r e 1.42 2.87 0 C h a n g e i n p r e s s u r e − x − 3 x + 2 x E q u i l i b r i u m p r e s s u r e 1.42 − x 2.87 − 3 x 2 x Now, these values in the fourth row can be inserted in the equilibrium constant expression as shown below. K = ( 2 x ) 2 ( 1.42 − x ) ( 2.87 − 3 x ) 3 By assuming x ≪ 1.42 a n d 2.87 , it can be written that 1.42 − x ≃ 1

7th Edition

ISBN: 9781319420994

Author: ATKINS

Publisher: MAC HIGHER

See similar textbooks

Videos

Question

Chapter 5, Problem 5I.22E

Interpretation Introduction

Interpretation:

The equilibrium partial pressure of each substance in the mixture has to be calculated. The reaction is given below.

N2(g)+3H2(g)⇌2NH3(g), K=0.036

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 5, Problem 5I.21E

Chapter 5, Problem 5I.23E

Students have asked these similar questions

What is the relationship between the limiting reactant and theoretical yield of CO2?

From your calculations, which reaction experiment had closest to stoichiometric quantities? How many moles of NaHCO3 and HC2H3O2 were present in this reaction?

18. Arrange the following carbocations in order of decreasing stability. 1 2 A 3124 B 4213 C 2431 D 1234 E 2134 SPL 3 4

Chapter 5 Solutions

CHEM PRINCIPLES LL W/ACHIEVE ONE-SEM

Ch. 5 - Prob. 5A.1AST Ch. 5 - Prob. 5A.1BST Ch. 5 - Prob. 5A.2AST Ch. 5 - Prob. 5A.2BST Ch. 5 - Prob. 5A.3AST Ch. 5 - Prob. 5A.3BST Ch. 5 - Prob. 5A.1E Ch. 5 - Prob. 5A.2E Ch. 5 - Prob. 5A.3E Ch. 5 - Prob. 5A.4E

Ch. 5 - Prob. 5A.5E Ch. 5 - Prob. 5A.6E Ch. 5 - Prob. 5A.7E Ch. 5 - Prob. 5A.8E Ch. 5 - Prob. 5A.11E Ch. 5 - Prob. 5B.1AST Ch. 5 - Prob. 5B.1BST Ch. 5 - Prob. 5B.2AST Ch. 5 - Prob. 5B.2BST Ch. 5 - Prob. 5B.3AST Ch. 5 - Prob. 5B.3BST Ch. 5 - Prob. 5B.1E Ch. 5 - Prob. 5B.2E Ch. 5 - Prob. 5B.3E Ch. 5 - Prob. 5B.5E Ch. 5 - Prob. 5B.7E Ch. 5 - Prob. 5C.1AST Ch. 5 - Prob. 5C.1BST Ch. 5 - Prob. 5C.2AST Ch. 5 - Prob. 5C.2BST Ch. 5 - Prob. 5C.3AST Ch. 5 - Prob. 5C.3BST Ch. 5 - Prob. 5C.1E Ch. 5 - Prob. 5C.3E Ch. 5 - Prob. 5C.4E Ch. 5 - Prob. 5C.5E Ch. 5 - Prob. 5C.6E Ch. 5 - Prob. 5C.7E Ch. 5 - Prob. 5C.8E Ch. 5 - Prob. 5C.9E Ch. 5 - Prob. 5C.10E Ch. 5 - Prob. 5C.11E Ch. 5 - Prob. 5C.12E Ch. 5 - Prob. 5C.15E Ch. 5 - Prob. 5C.16E Ch. 5 - Prob. 5D.1AST Ch. 5 - Prob. 5D.1BST Ch. 5 - Prob. 5D.1E Ch. 5 - Prob. 5D.2E Ch. 5 - Prob. 5D.3E Ch. 5 - Prob. 5D.4E Ch. 5 - Prob. 5D.5E Ch. 5 - Prob. 5D.6E Ch. 5 - Prob. 5D.7E Ch. 5 - Prob. 5D.8E Ch. 5 - Prob. 5D.9E Ch. 5 - Prob. 5D.10E Ch. 5 - Prob. 5D.11E Ch. 5 - Prob. 5D.12E Ch. 5 - Prob. 5D.13E Ch. 5 - Prob. 5D.14E Ch. 5 - Prob. 5D.15E Ch. 5 - Prob. 5D.16E Ch. 5 - Prob. 5D.18E Ch. 5 - Prob. 5D.19E Ch. 5 - Prob. 5D.20E Ch. 5 - Prob. 5E.1AST Ch. 5 - Prob. 5E.1BST Ch. 5 - Prob. 5E.2AST Ch. 5 - Prob. 5E.2BST Ch. 5 - Prob. 5E.1E Ch. 5 - Prob. 5E.2E Ch. 5 - Prob. 5E.11E Ch. 5 - Prob. 5E.12E Ch. 5 - Prob. 5F.1AST Ch. 5 - Prob. 5F.1BST Ch. 5 - Prob. 5F.2AST Ch. 5 - Prob. 5F.2BST Ch. 5 - Prob. 5F.3AST Ch. 5 - Prob. 5F.3BST Ch. 5 - Prob. 5F.4AST Ch. 5 - Prob. 5F.4BST Ch. 5 - Prob. 5F.5AST Ch. 5 - Prob. 5F.5BST Ch. 5 - Prob. 5F.1E Ch. 5 - Prob. 5F.2E Ch. 5 - Prob. 5F.3E Ch. 5 - Prob. 5F.5E Ch. 5 - Prob. 5F.7E Ch. 5 - Prob. 5F.9E Ch. 5 - Prob. 5F.10E Ch. 5 - Prob. 5F.11E Ch. 5 - Prob. 5F.12E Ch. 5 - Prob. 5F.13E Ch. 5 - Prob. 5F.14E Ch. 5 - Prob. 5F.15E Ch. 5 - Prob. 5F.16E Ch. 5 - Prob. 5G.1AST Ch. 5 - Prob. 5G.1BST Ch. 5 - Prob. 5G.2AST Ch. 5 - Prob. 5G.2BST Ch. 5 - Prob. 5G.3AST Ch. 5 - Prob. 5G.3BST Ch. 5 - Prob. 5G.4AST Ch. 5 - Prob. 5G.4BST Ch. 5 - Prob. 5G.5AST Ch. 5 - Prob. 5G.5BST Ch. 5 - Prob. 5G.1E Ch. 5 - Prob. 5G.2E Ch. 5 - Prob. 5G.3E Ch. 5 - Prob. 5G.4E Ch. 5 - Prob. 5G.7E Ch. 5 - Prob. 5G.8E Ch. 5 - Prob. 5G.9E Ch. 5 - Prob. 5G.11E Ch. 5 - Prob. 5G.12E Ch. 5 - Prob. 5G.13E Ch. 5 - Prob. 5G.14E Ch. 5 - Prob. 5G.15E Ch. 5 - Prob. 5G.16E Ch. 5 - Prob. 5G.17E Ch. 5 - Prob. 5G.19E Ch. 5 - Prob. 5G.20E Ch. 5 - Prob. 5G.21E Ch. 5 - Prob. 5G.22E Ch. 5 - Prob. 5H.1AST Ch. 5 - Prob. 5H.1BST Ch. 5 - Prob. 5H.2AST Ch. 5 - Prob. 5H.2BST Ch. 5 - Prob. 5H.1E Ch. 5 - Prob. 5H.2E Ch. 5 - Prob. 5H.3E Ch. 5 - Prob. 5H.4E Ch. 5 - Prob. 5H.5E Ch. 5 - Prob. 5H.6E Ch. 5 - Prob. 5I.1AST Ch. 5 - Prob. 5I.1BST Ch. 5 - Prob. 5I.2AST Ch. 5 - Prob. 5I.2BST Ch. 5 - Prob. 5I.3AST Ch. 5 - Prob. 5I.3BST Ch. 5 - Prob. 5I.4AST Ch. 5 - Prob. 5I.4BST Ch. 5 - Prob. 5I.1E Ch. 5 - Prob. 5I.2E Ch. 5 - Prob. 5I.3E Ch. 5 - Prob. 5I.4E Ch. 5 - Prob. 5I.5E Ch. 5 - Prob. 5I.6E Ch. 5 - Prob. 5I.7E Ch. 5 - Prob. 5I.9E Ch. 5 - Prob. 5I.10E Ch. 5 - Prob. 5I.11E Ch. 5 - Prob. 5I.12E Ch. 5 - Prob. 5I.13E Ch. 5 - Prob. 5I.14E Ch. 5 - Prob. 5I.15E Ch. 5 - Prob. 5I.16E Ch. 5 - Prob. 5I.17E Ch. 5 - Prob. 5I.18E Ch. 5 - Prob. 5I.19E Ch. 5 - Prob. 5I.20E Ch. 5 - Prob. 5I.21E Ch. 5 - Prob. 5I.22E Ch. 5 - Prob. 5I.23E Ch. 5 - Prob. 5I.24E Ch. 5 - Prob. 5I.25E Ch. 5 - Prob. 5I.26E Ch. 5 - Prob. 5I.27E Ch. 5 - Prob. 5I.28E Ch. 5 - Prob. 5I.29E Ch. 5 - Prob. 5I.30E Ch. 5 - Prob. 5I.32E Ch. 5 - Prob. 5I.33E Ch. 5 - Prob. 5I.34E Ch. 5 - Prob. 5I.35E Ch. 5 - Prob. 5I.36E Ch. 5 - Prob. 5J.1AST Ch. 5 - Prob. 5J.1BST Ch. 5 - Prob. 5J.3AST Ch. 5 - Prob. 5J.3BST Ch. 5 - Prob. 5J.4AST Ch. 5 - Prob. 5J.4BST Ch. 5 - Prob. 5J.5AST Ch. 5 - Prob. 5J.5BST Ch. 5 - Prob. 5J.1E Ch. 5 - Prob. 5J.2E Ch. 5 - Prob. 5J.3E Ch. 5 - Prob. 5J.4E Ch. 5 - Prob. 5J.5E Ch. 5 - Prob. 5J.6E Ch. 5 - Prob. 5J.9E Ch. 5 - Prob. 5J.10E Ch. 5 - Prob. 5J.11E Ch. 5 - Prob. 5J.12E Ch. 5 - Prob. 5J.13E Ch. 5 - Prob. 5J.17E Ch. 5 - Prob. 5.1E Ch. 5 - Prob. 5.2E Ch. 5 - Prob. 5.3E Ch. 5 - Prob. 5.4E Ch. 5 - Prob. 5.5E Ch. 5 - Prob. 5.6E Ch. 5 - Prob. 5.7E Ch. 5 - Prob. 5.8E Ch. 5 - Prob. 5.9E Ch. 5 - Prob. 5.10E Ch. 5 - Prob. 5.11E Ch. 5 - Prob. 5.12E Ch. 5 - Prob. 5.13E Ch. 5 - Prob. 5.14E Ch. 5 - Prob. 5.15E Ch. 5 - Prob. 5.16E Ch. 5 - Prob. 5.17E Ch. 5 - Prob. 5.19E Ch. 5 - Prob. 5.23E Ch. 5 - Prob. 5.24E Ch. 5 - Prob. 5.25E Ch. 5 - Prob. 5.26E Ch. 5 - Prob. 5.27E Ch. 5 - Prob. 5.28E Ch. 5 - Prob. 5.29E Ch. 5 - Prob. 5.30E Ch. 5 - Prob. 5.31E Ch. 5 - Prob. 5.32E Ch. 5 - Prob. 5.33E Ch. 5 - Prob. 5.35E Ch. 5 - Prob. 5.37E Ch. 5 - Prob. 5.38E Ch. 5 - Prob. 5.41E Ch. 5 - Prob. 5.43E Ch. 5 - Prob. 5.44E Ch. 5 - Prob. 5.45E Ch. 5 - Prob. 5.46E Ch. 5 - Prob. 5.47E Ch. 5 - Prob. 5.49E Ch. 5 - Prob. 5.51E Ch. 5 - Prob. 5.53E Ch. 5 - Prob. 5.55E Ch. 5 - Prob. 5.57E Ch. 5 - Prob. 5.58E Ch. 5 - Prob. 5.61E Ch. 5 - Prob. 5.62E

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The equilibrium partial pressure of each substance in the mixture has to be calculated. The reaction is given below. N 2 ( g ) + 3 H 2 ( g ) ⇌ 2 N H 3 ( g ) , K = 0.036

Solution Summary: The author explains how the equilibrium partial pressure of each substance in the mixture has to be calculated.

Videos

Interpretation:

The equilibrium partial pressure of each substance in the mixture has to be calculated. The reaction is given below.

N2(g)+3H2(g)⇌2NH3(g), K=0.036

Want to see the full answer?

Chapter 5 Solutions

The equilibrium partial pressure of each substance in the mixture has to be calculated. The reaction is given below. N 2 ( g ) + 3 H 2 ( g ) ⇌ 2 N H 3 ( g ) , K = 0.036

Solution Summary: The author explains how the equilibrium partial pressure of each substance in the mixture has to be calculated.

Videos

Interpretation: The equilibrium partial pressure of each substance in the mixture has to be calculated. The reaction is given below. N2(g)+3H2(g)⇌2NH3(g), K=0.036

Want to see the full answer?

Chapter 5 Solutions

Interpretation:

The equilibrium partial pressure of each substance in the mixture has to be calculated. The reaction is given below.

N2(g)+3H2(g)⇌2NH3(g), K=0.036