Chapter 5, Problem 5.98PAE

Interpretation Introduction

Interpretation: The noble gas with density $1.783\text{ g/L}$ at $0{}^{\circ }\text{C}$ and 1 atm needs to be identified.

Concept introduction:

The ideal gas law is mathematically expressed as:

$\text{PV}=\text{nRT}$

Number of moles of gas are related to mass of the gas as follows:

$\text{n}=\frac{\text{m}}{\text{M}}$

Here, M is molar mass of the gas.

Density is the ratio of mass to the volume or,

$\rho =\frac{\text{m}}{\text{V}}$

Here, V is volume of the gas.

Given:

Density of the given gas= $\text{1}\text{.783}\text{ g/L}$

Pressure of the gas= $\text{1}\text{ atm}$

Temperature of the gas= $0\text{ °C}=273\text{ K}$