The partial pressure of each of the gases in the undersea habitat which is 58.5 m below the sea level with the pressure of 6.91 atm has to be calculated Concept Introduction: Partial Pressure: Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures (P A , P B , P C ..... ) of all the component gases (A, B, C ...... ) present in the mixture” and is given as, P = P A + P B + P C + ....... The ideal gas law for the individual gas component A is given as, P A V = n A RT Mole fraction: Mole fraction of a component gas is defined as “the fraction of moles of that component in the total moles of gas mixture” and is given as, Mole fraction of A = n A n = P A P
The partial pressure of each of the gases in the undersea habitat which is 58.5 m below the sea level with the pressure of 6.91 atm has to be calculated Concept Introduction: Partial Pressure: Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures (P A , P B , P C ..... ) of all the component gases (A, B, C ...... ) present in the mixture” and is given as, P = P A + P B + P C + ....... The ideal gas law for the individual gas component A is given as, P A V = n A RT Mole fraction: Mole fraction of a component gas is defined as “the fraction of moles of that component in the total moles of gas mixture” and is given as, Mole fraction of A = n A n = P A P
Solution Summary: The author explains that the partial pressure of each of the gases in the undersea habitat, which is 58.5 m below the sea level, has to be calculated.
Study of body parts and their functions. In this combined field of study, anatomy refers to studying the body structure of organisms, whereas physiology refers to their function.
Chapter 5, Problem 5.86QP
Interpretation Introduction
Interpretation:
The partial pressure of each of the gases in the undersea habitat which is 58.5 m below the sea level with the pressure of 6.91 atm has to be calculated
Concept Introduction:
Partial Pressure:
Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures(PA, PB, PC.....) of all the component gases(A, B, C......) present in the mixture” and is given as,
P = PA + PB + PC + .......
The ideal gas law for the individual gas component A is given as,
PAV = nART
Mole fraction:
Mole fraction of a component gas is defined as “the fraction of moles of that component in the total moles of gas mixture” and is given as,
LTS
Solid:
AT=Te-Ti
Trial 1
Trial 2
Trial 3
Average
ΔΗ
Mass water, g
24.096
23.976
23.975
Moles of solid, mol
0.01763
001767
0101781
Temp. change, °C
2.9°C
11700
2.0°C
Heat of reaction, J
-292.37J -170.473
-193.26J
AH, kJ/mole
16.58K 9.647 kJ 10.85 kr
16.58K59.64701
KJ
mol
12.35k
Minimum AS,
J/mol K
41.582
mol-k
Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn &
Show your calculations for:
AH in J and then in kJ/mole for Trial 1:
qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J
qsin =
qrxn =
292.35 292.37J
AH in J = 292.375 0.2923kJ
0.01763m01
=1.65×107
AH in kJ/mol =
=
16.58K
0.01763mol
mol
qrx
Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con
Kelvin.)
AS=AHIT
(1.65×10(9.64×103) + (1.0
Jimai
For the compound: C8H17NO2
Use the following information to come up with a plausible structure:
8
This compound has "carboxylic acid amide" and ether functional groups.
The peaks at 1.2ppm are two signals that are overlapping one another.
One of the two signals is a doublet that represents 6 hydrogens; the
other signal is a quartet that represents 3 hydrogens.
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Chapter 5 Solutions
Student Solutions Manual for Ebbing/Gammon's General Chemistry, 11th
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