Explanation Given info: The volume of oxygen in the cylinder is 40 L , the temperature is 20 °C , the pressure is 17 MPa , the density of oxygen at 20 °C and atmospheric pressure of 101 kPa is 1.4 kg/m 3 Write the expression of Boyle’s law for gases. p 1 p 2 = V 2 V 1 ( at constant temperature ) Here, p 1 is the initial pressure p 2 is the final pressure V 1 is the initial volume V 2 is the final volume Let the initial pressure be the pressure of oxygen gas in the cylinder ( P cyl ), initial volume be the volume of the oxygen gas in the cylinder ( V cyl ), the final pressure be the atmospheric pressure ( P atm ) and final volume be the volume of oxygen gas corresponding to the density 1.4 kg/m 3 ( V atm ). Modify the expression of Boyle’s law using the above-described terms. p cyl p atm = V atm V cyl ( at constant temperature ) Solve for V atm

Connect with LearnSmart for Krauskopf: The Physical Universe, 16e

16th Edition

ISBN: 9781259663895

Author: KRAUSKOPF, Konrad B.

Publisher: Mcgraw-hill Higher Education (us)

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Variation of pressure

From the equation of pressure, pressure is directly proportional to the applied force.

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Chapter 5, Problem 57E

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The mass of oxygen in the cylinder.

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Chapter 5, Problem 56E

Chapter 5, Problem 58E

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The mass of oxygen in the cylinder.

Solution Summary: The author explains that the mass of oxygen in the cylinder is 9.4kg.

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The mass of oxygen in the cylinder.

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Chapter 5 Solutions