(a)
Interpretation:
Three different flasks that contain
Concept introduction:
The ideal gas equation can be expressed as follows:
Here,
The expression to calculate the moles of gas is as follows:
(b)
Interpretation:
Three different flasks that contain
Concept introduction:
The expression to calculate the average kinetic energy of gases is as follows:
Here,
The expression to calculate the kinetic energy is as follows:
The kinetic energy is directly proportional to the temperature.
(c)
Interpretation:
Three different flasks that contain
Concept introduction:
Effusion is explained as the movement of the gas molecule through a pinhole.
Diffusion can be explained as the mixing of one gas molecule with another gas molecule by random motion.
According to Graham’s law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
The mathematical expression of Graham’s law of effusion is as follows:
Here,
(d)
Interpretation:
Three different flasks that contain
Concept introduction:
The expression to calculate the root-mean-square speed is as follows:
Here,
The expression to calculate the average kinetic energy of gases is as follows:
Here,
The expression to calculate the kinetic energy is as follows:
The kinetic energy is directly proportional to the temperature.
(e)
Interpretation:
Three different flasks that contain
Concept introduction:
The expression to calculate the density of the air is as follows,
Here,
Rate of diffusion is inversely proportional to the square root of the density of the gas.
The expression to calculate the density of a gas is as follows:
(f)
Interpretation:
Three different flasks that contain
Concept introduction:
The mean free path can be defined as the average distance traveled by the gas molecule during a collision. There are many factors that affect the mean free path such as pressure, temperature, density and radius of the molecule.
The collision frequency is defined as the ratio of the most probable speed to the mean free path.
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Chapter 5 Solutions
CHEMISTRY: THE MOLECULAR NATURE OF MATTE
- Provide steps and explanation please.arrow_forwardDraw a structural formula for the major product of the acid-base reaction shown. H 0 N + HCI (1 mole) CH3 N' (1 mole) CH3 You do not have to consider stereochemistry. ● • Do not include counter-ions, e.g., Na+, I, in your answer. . In those cases in which there are two reactants, draw only the product from 989 CH3 344 ? [Farrow_forwardQuestion 15 What is the major neutral organic product for the following sequence? 1. POCI₂ pyridine ? 2. OsO4 OH 3. NaHSO Major Organic Product ✓ OH OH 'OH OH 'OH 'CIarrow_forward
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
- Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forwardPart 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forward
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