College Physics, Volume 1
College Physics, Volume 1
2nd Edition
ISBN: 9781133710271
Author: Giordano
Publisher: Cengage
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 5, Problem 54P
To determine

The gravitational force of Jupiter on the earth, and compare the result with the magnitude of gravitational force on earth from the sun.

Expert Solution & Answer
Check Mark

Answer to Problem 54P

The gravitational force of Jupiter on the earth when it is closest to earth is 1.9×1018N_, The gravitational force of Jupiter on the earth when earth is farthest to earth is 8.8×1017N_, and the gravitational force of the sun on the earth is 3.5×1022N_.

Explanation of Solution

Write the expression for gravitational force of the sun on the earth.

    FSEgrav=GMSunMEarthrEarth2        (I)

Here, FSEgrav is the gravitational force of the sun on the earth, G is the universal gravitation constant, MSun is the mass of the sun, MEarth is the mass of earth, and rEarth is the radius of earth.

Write the expression for gravitational force of Jupiter on the earth when it is closest to earth.

    FJupiter closest =GMJupiter MEarth (rJupiter rEarth )2        (II)

Here, FJupiter closest  is the gravitational force of Jupiter on the earth when it is closest to earth,  MJupiter  is the mass of Jupiter, and rJupiter  is the radius of Jupiter.

Write the expression for gravitational force of Jupiter on the earth when it is furthest to earth.

    FJupiter Furthest =GMJupiter MEarth (rJupiter +rEarth )2        (III)

Here, FJupiter Furthest  is the gravitational force of Jupiter on the earth when it is furthest to earth, MJupiter  is the mass of Jupiter, and rJupiter  is the radius of Jupiter.

Conclusion:

Substitute 6.67×1011Nm2/kg for G, 1.99×1030kg for Msun, 1.50×1011m for rE and 5.97×1024kg for MEarth in equation (I), to find FSEgrav.

    FSEgrav=(6.67×1011Nm2/kg)(1.99×1030kg)(5.97×1024kg)(1.50×1011m)2=3.5×1022N

Substitute 6.67×1011Nm2/kg for G, 1.99×1027kg for MJupiter, 1.50×1011m for rEarth, 7.78×1011m for rJupiter and 5.97×1024kg for MEarth in equation (II), to find FJupiter closest .

    FJupiter closest =(6.67×1011Nm2/kg)(1.99×1027kg)(1.50×1011m)((7.78×1011m)(5.97×1024kg))2=1.9×1018N

Substitute 6.67×1011Nm2/kg for G, 1.99×1027kg for MJupiter, 1.50×1011m for rEarth, 7.78×1011m for rJupiter and 5.97×1024kg for MEarth in equation (III), to find FJupiter furthest.

    FJupiter furthest=(6.67×1011Nm2/kg)(1.99×1027kg)(1.50×1011m)((7.78×1011m)+(5.97×1024kg))2=8.8×1017N

Therefore, the gravitational force of Jupiter on the earth when it is closest to earth is 1.9×1018N_, The gravitational force of Jupiter on the earth when earth is farthest to earth is 8.8×1017N_, and the gravitational force of the sun on the earth is 3.5×1022N_.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
The human eye is most sensitive to light having a frequency of about 5.5 × 1014 Hz, which is in the yellow-green region of the electromagnetic spectrum. How many wavelengths of this light can fit across a distance of 2.2 cm?
A one-dimensional harmonic oscillator of mass m and angular frequency w is in a heat bath of temperature T. What is the root mean square of the displacement of the oscillator? (In the expressions below k is the Boltzmann constant.) Select one: ○ (KT/mw²)1/2 ○ (KT/mw²)-1/2 ○ kT/w O (KT/mw²) 1/2In(2)
Two polarizers are placed on top of each other so that their transmission axes coincide. If unpolarized light falls on the system, the transmitted intensity is lo. What is the transmitted intensity if one of the polarizers is rotated by 30 degrees? Select one: ○ 10/4 ○ 0.866 lo ○ 310/4 01/2 10/2

Chapter 5 Solutions

College Physics, Volume 1

Ch. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - What force makes it possible for a car to move...Ch. 5 - Prob. 9QCh. 5 - Prob. 10QCh. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Plutos mass. In 1978, it was discovered that Pluto...Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10PCh. 5 - A compact disc spins at 2.5 revolutions per...Ch. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Consider the motion of a rock tied to a string of...Ch. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 29PCh. 5 - Consider a Ferris wheel in which the chairs hang...Ch. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - A rock of mass m is tied to a string of length L...Ch. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77P
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Newton's First Law of Motion: Mass and Inertia; Author: Professor Dave explains;https://www.youtube.com/watch?v=1XSyyjcEHo0;License: Standard YouTube License, CC-BY