Organic Chemistry (9th Edition)
Organic Chemistry (9th Edition)
9th Edition
ISBN: 9780321971371
Author: Leroy G. Wade, Jan W. Simek
Publisher: PEARSON
Question
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Chapter 5, Problem 5.36SP

(a)

Interpretation Introduction

To determine: The mechanism that corresponds to occurrence of free radical halogenations exclusively at the benzylic position.

Interpretation: A mechanism that corresponds to the reason as to why free radical halogenations occurred exclusively at the benzylic position is to be proposed.

Concept introduction: Free radical bromination occurs exclusively at the benzylic position. The benzylic position is next to the aromatic ring. In the first step, there is homolytic cleavage of bromine molecule. The electrons are shared equally among both the bromine atoms. Bromine abstracts the benzylic proton from the given compound to result in the formation of HBr and a sp2 planar benzylic carbon. The benzylic radical is resonance stablised.

(b)

Interpretation Introduction

To draw: The two stereoisomers that result from the monobromination at the benzylic position.

Interpretation: The structure of the two stereoisomers that result from the monobromination at the benzylic position is to be drawn.

Concept introduction: Stereoisomers are further divided into two categories: optical isomers and geometrical isomers. The two different forms in which a single chiral carbon can exist is referred to as enantiomers. The class of diastereomers includes stereoisomers that are not enantiomers.

(c)

Interpretation Introduction

To determine: The R and S configurations of the asymmetric carbon atoms in the product.

Interpretation: The R and S configurations to the asymmetric carbon atoms in the product are to be assigned.

Concept introduction: The enantiomers of a chiral compound can be named with the help of right hand and left hand configuration. In fisher projection, chiral carbon atom is represented by a cross. When two groups on a fisher projection are interchanged, the configuration of chiral carbon also changes from (R) to (S) or (S) to (R).

(d)

Interpretation Introduction

To determine: The relationship between the isomeric products.

Interpretation: The relationship between the isomeric products is to be stated.

Concept introduction: Stereoisomers are further divided into two categories: optical isomers and geometrical isomers. The two different forms in which a single chiral carbon can exist is referred to as enantiomers. The class of diastereomers includes stereoisomers that are not enantiomers.

(e)

Interpretation Introduction

To determine: If the products are produced in identical amounts.

Interpretation: The validation of the fact that the products are formed in equal amounts is to be stated.

Concept introduction: Stereoisomers are further divided into two categories: optical isomers and geometrical isomers. The two different forms in which a single chiral carbon can exist is referred to as enantiomers. The class of diastereomers includes stereoisomers that are not enantiomers.

(f)

Interpretation Introduction

To determine: If the products have identical physical properties.

Interpretation: The validation of the fact that the products have identical physical properties is to be stated.

Concept introduction: Stereoisomers are further divided into two categories: optical isomers and geometrical isomers. The two different forms in which a single chiral carbon can exist is referred as enantiomers. The class of diastereomers includes stereoisomers that are not enantiomers.

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Resveratrol is an antioxidant found in the skin of red grapes. Its anticancer, anti-inflammatory, and various cardiovascular effects are under active investigation. (a) Draw all resonance structures for the radical that results from homolysis of the OH bond shown in red. (b) Explain why homolysis of this OH bond is preferred to homolysis of either OH bond in the other benzene ring.
Resveratrol is an antioxidant found in the skin of red grapes. Its anticancer, anti-inammatory, and various cardiovascular effects are under active investigation. (a) Draw all resonance structures for the radical that results from homolysis of the OH bond shown in red. (b) Explain why homolysis of this OH bond is preferred to homolysis of either OH bond in the other benzene ring.
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