Get Ready for Organic Chemistry
2nd Edition
ISBN: 9780321774125
Author: KARTY, Joel
Publisher: PEARSON
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Chapter 5, Problem 5.26P
Interpretation Introduction
Interpretation:
Among the given molecules, which molecule has a different acidity than Y, is to be identified.
Concept introduction:
In order to be isomers, two compounds should have the same molecular formula.
Isomers are the molecules having same molecular formula but different structural formula or different configuration. Constitutional isomers must have different physical and chemical properties. In an achiral environment, enantiomers have exactly the same physical and chemical properties. In a chiral environment, enantiomers show different physical and chemical properties. Depending on a specific situation, the behavior of enantiomers can be slightly or dramatically different. Diastereomers show different physical and chemical properties. Enantiomers and diastereomers are configurational isomers of each other having the same connectivity.
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5 (a). Using the peak information you listed in the tables for
both structures, assign each peak to that portion of the
structure that produces the peak in the NMR spectrum. Draw
this diagram on your own sheet of paper and attach the sketch
of your drawing to this question.
Question 6
5 (b). Using the peak information you listed in the tables for
both structures, assign each peak to that portion of the
structure that produces the peak in the NMR spectrum. Draw
this diagram on your own sheet of paper and attach the sketch
of your drawing to this question.
Question 7
6. Are there any differences between the spectra you obtained
in Beyond Labz and the predicted spectra? If so, what were
the differences?
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2. Predict the NMR spectra for each of these two
compounds by listing, in the NMR tables below, the
chemical shift, the splitting, and the number of
hydrogens associated with each predicted peak. Sort the
peaks from largest chemical shift to lowest.
**Not all slots must be filled**
Peak
Chemical Shift (d)
5.7
1
Multiplicity
multiplate
..........
5.04
double of doublet
2
4.98
double of doublet
3
4.05
doublet of quartet
4
5
LO
3.80
quartet
1.3
doublet
6
Peak
Chemical Shift (d)
Multiplicity
Chapter 5 Solutions
Get Ready for Organic Chemistry
Ch. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10P
Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. 5.48PCh. 5 - Prob. 5.49PCh. 5 - Prob. 5.50PCh. 5 - Prob. 5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. 5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67PCh. 5 - Prob. 5.68PCh. 5 - Prob. 5.69PCh. 5 - Prob. 5.70PCh. 5 - Prob. 5.71PCh. 5 - Prob. 5.72PCh. 5 - Prob. 5.73PCh. 5 - Prob. 5.74PCh. 5 - Prob. 5.75PCh. 5 - Prob. 5.76PCh. 5 - Prob. 5.77PCh. 5 - Prob. 5.78PCh. 5 - Prob. 5.79PCh. 5 - Prob. 5.1YTCh. 5 - Prob. 5.2YTCh. 5 - Prob. 5.3YTCh. 5 - Prob. 5.4YTCh. 5 - Prob. 5.5YTCh. 5 - Prob. 5.6YTCh. 5 - Prob. 5.7YTCh. 5 - Prob. 5.8YTCh. 5 - Prob. 5.9YTCh. 5 - Prob. 5.10YTCh. 5 - Prob. 5.11YTCh. 5 - Prob. 5.12YTCh. 5 - Prob. 5.13YTCh. 5 - Prob. 5.14YTCh. 5 - Prob. 5.15YTCh. 5 - Prob. 5.16YTCh. 5 - Prob. 5.17YT
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- Interpreting NMR spectra is a skill that often requires some amount of practice, which, in turn, necessitates access to a collection of NMR spectra. Beyond Labz Organic Synthesis and Organic Qualitative Analysis have spectral libraries containing over 700 1H NMR spectra. In this assignment, you will take advantage of this by first predicting the NMR spectra for two closely related compounds and then checking your predictions by looking up the actual spectra in the spectra library. After completing this assignment, you may wish to select other compounds for additional practice. 1. Write the IUPAC names for the following two structures: Question 2 Question 3 2. Predict the NMR spectra for each of these two compounds by listing, in the NMR tables below, the chemical shift, the splitting, and the number of hydrogens associated with each predicted peak. Sort the peaks from largest chemical shift to lowest. **Not all slots must be filled**arrow_forward11:14 ... worksheets.beyondlabz.com 3. To check your predictions, click this link for Interpreting NMR Spectra 1. You will see a list of all the - compounds in the spectra library in alphabetical order by IUPAC name. Hovering over a name in the list will show the structure on the chalkboard. The four buttons on the top of the Spectra tab in the tray are used to select the different spectroscopic techniques for the selected compound. Make sure the NMR button has been selected. 4. Scroll through the list of names to find the names for the two compounds you have been given and click on the name to display the NMR spectrum for each. In the NMR tables below, list the chemical shift, the splitting, and the number of hydrogens associated with each peak for each compound. Compare your answers to your predictions. **Not all slots must be filled** Peak Chemical Shift (d) Multiplicity 1 2 3 4 5arrow_forwardО δα HO- H -Br δα HO-- + + -Br [B] 8+ HO- -Br δα नarrow_forward
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