The change in volume of a given mass of gas at STP has to be calculated Concept Introduction: Combined Gas Law : Boyle’s law: V α 1 P (at constant T) P f V f = P i V i (at constant T) Charles’s law: V α T (at constant P) V f T f = V i T i (at constant P) The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)” V α T P For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as P f V f T f = P i V i T i Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively P i a n d P f are initial pressure and final pressure respectively
The change in volume of a given mass of gas at STP has to be calculated Concept Introduction: Combined Gas Law : Boyle’s law: V α 1 P (at constant T) P f V f = P i V i (at constant T) Charles’s law: V α T (at constant P) V f T f = V i T i (at constant P) The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)” V α T P For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as P f V f T f = P i V i T i Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively P i a n d P f are initial pressure and final pressure respectively
Solution Summary: The author explains that the change in volume of a given mass of gas at STP has to be calculated.
Study of body parts and their functions. In this combined field of study, anatomy refers to studying the body structure of organisms, whereas physiology refers to their function.
Chapter 5, Problem 5.138QP
Interpretation Introduction
Interpretation:
The change in volume of a given mass of gas at STP has to be calculated
Concept Introduction:
Combined Gas Law:
Boyle’s law:
Vα1P (at constant T)
PfVf=PiVi (at constant T)
Charles’s law:
Vα T (at constant P)
VfTf=ViTi (at constant P)
The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)”
VαTP
For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as
PfVfTf=PiViTi
Where,
Tiand Tf are initial temperature and final temperature respectively
Viand Vf are initial volume and final volume respectively
Piand Pf are initial pressure and final pressure respectively
Solve for x, where M is molar and s is seconds.
x = (9.0 × 10³ M−². s¯¹) (0.26 M)³
Enter the answer. Include units. Use the exponent key above the answer box to indicate any exponent on your units.
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0
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 5 Solutions
OWLv2 with Student Solutions Manual eBook for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 4 terms (24 months)
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