Ground source heat pumps operate by using the soil, rather than ambient air, as the heat source (or sink) for heating (or cooling) a building. A liquid transfers energy from (to) the soil by way of buried plastic tubing. The tubing is at a depth for which annual variations in the temperature of the soil are much less than those of the ambient air. For example, at a location such as South Bend, Indiana, deep-ground temperatures may remain at approximately 11 ° C, while annual excursions in the ambient air temperature may range from − 25 ° C to + 37 ° C . Consider the tubing to be laid out in a closely spaced serpentine arrangement. To what depth should the tubing be buried so that the soil can be viewed as an infinite medium at constant temperature over a 12-month period? Account for the periodic cooling (heating) of the soil due to both annual changes in ambient conditions and variations in heat pump operation from the winter heating to the summer cooling mode.
Ground source heat pumps operate by using the soil, rather than ambient air, as the heat source (or sink) for heating (or cooling) a building. A liquid transfers energy from (to) the soil by way of buried plastic tubing. The tubing is at a depth for which annual variations in the temperature of the soil are much less than those of the ambient air. For example, at a location such as South Bend, Indiana, deep-ground temperatures may remain at approximately 11 ° C, while annual excursions in the ambient air temperature may range from − 25 ° C to + 37 ° C . Consider the tubing to be laid out in a closely spaced serpentine arrangement. To what depth should the tubing be buried so that the soil can be viewed as an infinite medium at constant temperature over a 12-month period? Account for the periodic cooling (heating) of the soil due to both annual changes in ambient conditions and variations in heat pump operation from the winter heating to the summer cooling mode.
Solution Summary: The author illustrates the variation in temperature of soil because of buried plastic tubing and ambient air.
Ground source heat pumps operate by using the soil, rather than ambient air, as the heat source (or sink) for heating (or cooling) a building. A liquid transfers energy from (to) the soil by way of buried plastic tubing. The tubing is at a depth for which annual variations in the temperature of the soil are much less than those of the ambient air. For example, at a location such as South Bend, Indiana, deep-ground temperatures may remain at approximately
11
°
C,
while annual excursions in the ambient air temperature may range from
−
25
°
C
to
+
37
°
C
.
Consider the tubing to be laid out in a closely spaced serpentine arrangement.
To what depth should the tubing be buried so that the soil can be viewed as an infinite medium at constant temperature over a 12-month period? Account for the periodic cooling (heating) of the soil due to both annual changes in ambient conditions and variations in heat pump operation from the winter heating to the summer cooling mode.
A bent tube is attached to a wall with brackets as shown. A
force of F = 785 lb is applied to the end of the tube with
direction indicated by the dimensions in the figure.
a.) Determine the moment about point D due to the force F
Enter your answer in Cartesian components with units of ft-
lbs.
b.) Determine the moment about a line (i.e. axis) running
from D to C due to the force F. Enter your answer in
Cartesian components with units of ft-lbs.
2013 Michael Swanbom
x
BY NC SA
g
Z
h
A
с
FK
kaz
Values for dimensions on the figure are given in the table
below. Note the figure may not be to scale. Be sure to align
your cartesian unit vectors with the coordinate axes shown in
the figure.
Variable Value
α
4.84 in
b
13.2 in
с
12.5 in
d
30.8 in
h
18.7 in
22.0 in
→>
a. MD=(
i+
k) ft-
lb
→>
b. MDC =
î +
k) ft-
lb
F1
3
4
5
P
F2
F2
Ꮎ
e
b
200
3
4
5
F1
The electric pole is subject to the forces shown. Force F1
245 N and force F2 = 310 N with an angle 0 = 20.2°.
Determine the moment about point P of all forces. Take
counterclockwise moments to be positive.
=
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable Value
a
2.50 m
b
11.3 m
с
13.0 m
The moment about point P is
m.
N-
If the moment about point P sums up to be zero. Determine
the distance c while all other values remained the same.
m.
F
y
b
C
10
Z
Determine the moment about O due to the force F shown,
the magnitude of the force F = 76.0 lbs. Note: Pay attention
to the axis.
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable Value
a
1.90 ft
b
2.80 ft
с
2.60 ft
d
2.30 ft
Mo
=
lb
+
k) ft-
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