
Concept explainers
(a)
Interpretation:
The
Concept introduction:
Elements which have same

Answer to Problem 40E
The atomic mass of the element is
Explanation of Solution
The percentage abundances and atomic masses (u) of the natural isotopes of an element are given as shown below.
The contribution of the isotope to the atomic mass of element is calculated by the formula as shown below.
Substitute the values of percentage abundance and atomic mass of the first isotope in equation (1).
Substitute the values of percentage abundance and atomic mass of the second isotope in equation (1).
Substitute the values of percentage abundance and atomic mass of the third isotope in equation (1).
Substitute the values of percentage abundance and atomic mass of the fourth isotope in equation (1).
Substitute the values of percentage abundance and atomic mass of the fifth isotope in equation (1).
The atomic mass of the element is equal to the sum of atomic masses of its five isotopes.
Therefore, the atomic mass of the element is calculated as shown below.
Therefore, the atomic mass of the element is
The atomic mass of the element is
(b)
Interpretation:
The name of the element is to be identified.
Concept introduction:
Elements which have same atomic number but different atomic mass are known as isotopes. The atomic mass of an element is defined as the total mass of one atom of an element. Its unit is atomic mass unit

Answer to Problem 40E
The name of the element is cerium
Explanation of Solution
The calculated atomic mass of the element is
In the periodic table, the element having atomic mass
Therefore, the name of the element is nickel
The element having
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Chapter 5 Solutions
Introductory Chemistry: An Active Learning Approach
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