Enhanced Discovering Computers, Fundamentals: Your Interactive Guide To The Digital World, 2013 Edition (shelly Cashman)
1st Edition
ISBN: 9781133596448
Author: Misty E. Vermaat
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Expert Solution & Answer
Chapter 5, Problem 3CT
Explanation of Solution
Differences between hacker and crackers are as follows:
| Hackers | Crackers |
| People who can access other computers without owner’s permission are referred as hackers. | People who can access the computer without permission and also having the capability to destroy the data and stealing important data are referred as crackers. |
| Hacker has advanced skills to access any computer. | Cracker has advanced skills to destroy any important data... |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
digital image processing By finding the necessary coding for the symbols according to the given symbol probability table, calculate code symbol for "001000011010000010110011". Note that in the initial state, the probability of 0,55 is expressed as 0 and the probability of 0,45 is 1.What is the last symbol of the result from the Huffman coding?A) a4 B) a6 C)a1 D) a3
digital image processingWhat is the number of dark small square in set B after (B ⊕X)?a) 29b) 32c) 35d) Other
digital image processingWhat is the number of dark small square in set A after (A θ Y)?a) 26b) 24c) 22d) Other
Chapter 5 Solutions
Enhanced Discovering Computers, Fundamentals: Your Interactive Guide To The Digital World, 2013 Edition (shelly Cashman)
Ch. 5 - Prob. 1SGCh. 5 - Prob. 2SGCh. 5 - Prob. 3SGCh. 5 - Prob. 4SGCh. 5 - Prob. 5SGCh. 5 - Prob. 6SGCh. 5 - Prob. 7SGCh. 5 - Prob. 8SGCh. 5 - Prob. 9SGCh. 5 - Prob. 10SG
Ch. 5 - Prob. 11SGCh. 5 - Prob. 12SGCh. 5 - Prob. 13SGCh. 5 - Prob. 14SGCh. 5 - Prob. 15SGCh. 5 - Prob. 16SGCh. 5 - Prob. 17SGCh. 5 - Prob. 18SGCh. 5 - Prob. 19SGCh. 5 - Prob. 20SGCh. 5 - Prob. 21SGCh. 5 - Prob. 22SGCh. 5 - Prob. 23SGCh. 5 - Prob. 24SGCh. 5 - Prob. 25SGCh. 5 - Prob. 26SGCh. 5 - Prob. 27SGCh. 5 - Prob. 28SGCh. 5 - Prob. 29SGCh. 5 - Prob. 30SGCh. 5 - Prob. 31SGCh. 5 - Prob. 32SGCh. 5 - Prob. 33SGCh. 5 - Prob. 34SGCh. 5 - Prob. 35SGCh. 5 - Prob. 36SGCh. 5 - Prob. 37SGCh. 5 - Prob. 38SGCh. 5 - Prob. 39SGCh. 5 - Prob. 40SGCh. 5 - Prob. 41SGCh. 5 - Prob. 42SGCh. 5 - Prob. 43SGCh. 5 - Prob. 44SGCh. 5 - Prob. 45SGCh. 5 - Prob. 46SGCh. 5 - Prob. 47SGCh. 5 - Prob. 48SGCh. 5 - Prob. 49SGCh. 5 - Prob. 1TFCh. 5 - Prob. 2TFCh. 5 - Prob. 3TFCh. 5 - Prob. 4TFCh. 5 - Prob. 5TFCh. 5 - Prob. 6TFCh. 5 - Prob. 7TFCh. 5 - Prob. 8TFCh. 5 - Prob. 9TFCh. 5 - Prob. 10TFCh. 5 - Prob. 11TFCh. 5 - Prob. 12TFCh. 5 - Prob. 1MCCh. 5 - Prob. 2MCCh. 5 - Prob. 3MCCh. 5 - Prob. 4MCCh. 5 - Prob. 5MCCh. 5 - Prob. 6MCCh. 5 - Prob. 7MCCh. 5 - Prob. 8MCCh. 5 - Prob. 1MCh. 5 - Prob. 2MCh. 5 - Prob. 3MCh. 5 - Prob. 4MCh. 5 - Prob. 5MCh. 5 - Prob. 6MCh. 5 - Prob. 7MCh. 5 - Prob. 8MCh. 5 - Prob. 9MCh. 5 - Prob. 10MCh. 5 - Prob. 2CTCh. 5 - Prob. 3CTCh. 5 - Prob. 4CTCh. 5 - Prob. 5CTCh. 5 - Prob. 6CTCh. 5 - Prob. 7CTCh. 5 - Prob. 8CTCh. 5 - Prob. 9CTCh. 5 - Prob. 10CTCh. 5 - Prob. 11CTCh. 5 - Prob. 12CTCh. 5 - Prob. 13CTCh. 5 - Prob. 14CTCh. 5 - Prob. 15CTCh. 5 - Prob. 16CTCh. 5 - Prob. 17CTCh. 5 - Prob. 18CTCh. 5 - Prob. 19CTCh. 5 - Prob. 20CTCh. 5 - Prob. 21CTCh. 5 - Prob. 22CTCh. 5 - Prob. 23CTCh. 5 - Prob. 24CTCh. 5 - Prob. 25CTCh. 5 - Prob. 26CTCh. 5 - Prob. 27CTCh. 5 - Prob. 28CTCh. 5 - Prob. 29CTCh. 5 - Prob. 1PSCh. 5 - Prob. 2PSCh. 5 - Prob. 3PSCh. 5 - Prob. 4PSCh. 5 - Prob. 5PSCh. 5 - Prob. 6PSCh. 5 - Prob. 7PSCh. 5 - Prob. 8PSCh. 5 - Prob. 9PSCh. 5 - Prob. 10PSCh. 5 - Prob. 11PSCh. 5 - Prob. 1.1ECh. 5 - Prob. 1.2ECh. 5 - Prob. 1.3ECh. 5 - Prob. 2.1ECh. 5 - Prob. 2.2ECh. 5 - Prob. 2.3ECh. 5 - Prob. 3.3ECh. 5 - Prob. 4.1ECh. 5 - Prob. 4.2ECh. 5 - Prob. 4.3ECh. 5 - Prob. 5.1ECh. 5 - Prob. 5.2ECh. 5 - Prob. 5.3ECh. 5 - Prob. 1IRCh. 5 - Prob. 2IRCh. 5 - Prob. 3IRCh. 5 - Prob. 4IRCh. 5 - Prob. 5IRCh. 5 - Prob. 1CTQCh. 5 - Prob. 2CTQCh. 5 - Prob. 3CTQCh. 5 - Prob. 4CTQ
Knowledge Booster
Similar questions
- digital image processingWhat is the number of dark small square in set A after (A θ X)? a) 22b) 24c) 20d) Otherarrow_forwarddigital image processing By finding the necessary coding for the symbols according to the given symbol probability table, calculate code symbol for "001000011010000010110011". Note that in the initial state, the probability of 0,55 is expressed as 0 and the probability of 0,45 is 1.What is the first symbol of the result from the Huffman coding?A)=a6 B)=a3 C)=a1 D)=a2arrow_forwarddigital image processing(Using the transformation function shown in the figure below, apply contrast stretching for following input image A[2*2]. Where L=256.Find the output image B [2*2].)create output ımage C accordıng to the last three (3) least signifcantbits by bit plane slicing on image Aplease step by explaningarrow_forward
- Given a 16-bit word of 1011011001101001 read from memory, and assuming the original check bits were 10101, apply the Hamming error correction code to: a)Find the new check b)Calculate the syndrome c)Determine whether there is an error in the received word, and if so, correct it to find the original word stored in memoryarrow_forwardThis is a question that I have and would like someone who has experiences with scene graphs and entity component systems to answer.For context, I am currently implementing a game engine and currently I am debating on our current design.Our current design is we have a singular game component class that every component inherits from. Where we have components like SpriteRendererComponent, Mehs Component, etc. They inherit from this GameComponent class. The point of this is being able to have O(1) access to the scene to being able to modify components to attach more components with the idea of accessing those components to specific scene objects in a scene.Now, my question is what kinds of caveauts can this cause in terms of cache coherence? I am well aware that yes its O(1) and that is great but cache coherence is going to be really bad, but would like to know more explicit details and real-life examples such as write in RAM examples on how this is bad. A follow-up question that is part…arrow_forwardQ4: Consider the following MAILORDER relational schema describing the data for a mail order company. (Choose five only). PARTS(Pno, Pname, Qoh, Price, Olevel) CUSTOMERS(Cno, Cname, Street, Zip, Phone) EMPLOYEES(Eno, Ename, Zip, Hdate) ZIP CODES(Zip, City) ORDERS(Ono, Cno, Eno, Received, Shipped) ODETAILS(Ono, Pno, Qty) (10 Marks) I want a detailed explanation to understand the mechanism how it is Qoh stands for quantity on hand: the other attribute names are self-explanatory. Specify and execute the following queries using the RA interpreter on the MAILORDER database schema. a. Retrieve the names of parts that cost less than $20.00. b. Retrieve the names and cities of employees who have taken orders for parts costing more than $50.00. c. Retrieve the pairs of customer number values of customers who live in the same ZIP Code. d. Retrieve the names of customers who have ordered parts from employees living in Wichita. e. Retrieve the names of customers who have ordered parts costing less…arrow_forward
- Q4: Consider the following MAILORDER relational schema describing the data for a mail order company. (Choose five only). (10 Marks) PARTS(Pno, Pname, Qoh, Price, Olevel) CUSTOMERS(Cno, Cname, Street, Zip, Phone) EMPLOYEES(Eno, Ename, Zip, Hdate) ZIP CODES(Zip, City) ORDERS(Ono, Cno, Eno, Received, Shipped) ODETAILS(Ono, Pno, Qty) Qoh stands for quantity on hand: the other attribute names are self-explanatory. Specify and execute the following queries using the RA interpreter on the MAILORDER database schema. a. Retrieve the names of parts that cost less than $20.00. b. Retrieve the names and cities of employees who have taken orders for parts costing more than $50.00. c. Retrieve the pairs of customer number values of customers who live in the same ZIP Code. d. Retrieve the names of customers who have ordered parts from employees living in Wichita. e. Retrieve the names of customers who have ordered parts costing less than$20.00. f. Retrieve the names of customers who have not placed…arrow_forwardut da Q4: Consider the LIBRARY relational database schema shown in Figure below a. Edit Author_name to new variable name where previous surname was 'Al - Wazny'. Update book_Authors set Author_name = 'alsaadi' where Author_name = 'Al - Wazny' b. Change data type of Phone to string instead of numbers. عرفنه شنو الحل BOOK Book id Title Publisher_name BOOK AUTHORS Book id Author_name PUBLISHER Name Address Phone e u al b are rage c. Add two Publishers Company existed in UK. insert into publisher(name, address, phone) value('ali','uk',78547889), ('karrar', 'uk', 78547889) d. Remove all books author when author name contains second character 'D' and ending by character 'i'. es inf rmar nce 1 tic عرفته شنو الحل e. Add one book as variables data? عرفته شنو الحلarrow_forwardAdd a timer in the following code. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long elapsedTime; public GameGUI(Labyrinth labyrinth, Player player, Dragon dragon) { this.labyrinth = labyrinth; this.player = player; this.dragon = dragon; String playerName = JOptionPane.showInputDialog("Enter your name:"); player.setName(playerName); elapsedTime = 0; timer = new Timer(1000, e -> { elapsedTime++; repaint(); }); timer.start(); } @Override protected void paintComponent(Graphics g) { super.paintComponent(g); int cellSize = Math.min(getWidth() / labyrinth.getSize(), getHeight() / labyrinth.getSize());}arrow_forward
- Change the following code so that when player wins the game, the game continues by creating new GameGUI with the same player. However the player's starting position is same, everything else should be reseted. public static void main(String[] args) { Labyrinth labyrinth = new Labyrinth(10); Player player = new Player(9, 0); Random rand = new Random(); Dragon dragon = new Dragon(rand.nextInt(10), 9); JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon); frame.setLayout(new BorderLayout()); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.add(gui, BorderLayout.CENTER); frame.pack(); frame.setResizable(false); frame.setVisible(true); } public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long…arrow_forwardCreate a menu item which restarts the game. Also add a timer, which counts the elapsed time since the start of the game level. When the restart is pressed, the restarted game should ask the player' name (in the GameGUI constructor) and set the score of player to 0 (player.setScore(0)), and the timer should restart again. And create a logic so that if the player loses his life (checkGame if the condition is false), then save this number together with his name into two variables. And display two buttons where one quits the game altogether (System.exit(0)) and the other restarts the game. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private final ImageIcon playerIcon = new ImageIcon("data/images/player.png"); private final ImageIcon dragonIcon = new ImageIcon("data/images/dragon.png"); private final ImageIcon wallIcon = new ImageIcon("data/images/wall.png"); private final ImageIcon…arrow_forwardPlease original work Analyze the complexity issues of processing big data What are five complexities and talk about the reasons they make the implementation complex. Please cite in text references and add weblinksarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Information Systems (MindTap Course...Computer ScienceISBN:9781285867168Author:Ralph Stair, George ReynoldsPublisher:Cengage Learning
Enhanced Discovering Computers 2017 (Shelly Cashm...Computer ScienceISBN:9781305657458Author:Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. CampbellPublisher:Cengage Learning
Principles of Information Systems (MindTap Course...
Computer Science
ISBN:9781285867168
Author:Ralph Stair, George Reynolds
Publisher:Cengage Learning
Enhanced Discovering Computers 2017 (Shelly Cashm...
Computer Science
ISBN:9781305657458
Author:Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell
Publisher:Cengage Learning