
Fundamentals of Thermal-Fluid Sciences
5th Edition
ISBN: 9780078027680
Author: Yunus A. Cengel Dr., Robert H. Turner, John M. Cimbala
Publisher: McGraw-Hill Education
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Chapter 5, Problem 39P
To determine
The work done and heat transfer during the process.
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تكنولوجيا السيارات
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Chapter 5 Solutions
Fundamentals of Thermal-Fluid Sciences
Ch. 5 - Prob. 1PCh. 5 - Nitrogen at an initial state of 300 K, 150 kPa,...Ch. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - A piston–cylinder device with a set of stops...Ch. 5 - A piston–cylinder device initially contains 0.07...Ch. 5 - A mass of 5 kg of saturated water vapor at 300 kPa...Ch. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - A mass of 1.5 kg of air at 120 kPa and 24°C is...
Ch. 5 - Prob. 11PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - During an expansion process, the pressure of a gas...Ch. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - 0.75-kg water that is initially at 0.5 MPa and 30...Ch. 5 - Prob. 22PCh. 5 - A piston–cylinder device contains 50 kg of water...Ch. 5 - Reconsider Prob. 5–23. Using an appropriate...Ch. 5 - Prob. 25PCh. 5 - A closed system undergoes a process in which there...Ch. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - A fixed mass of saturated water vapor at 400 kPa...Ch. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 36PCh. 5 - A 40-L electrical radiator containing heating oil...Ch. 5 - Prob. 38PCh. 5 - Saturated R-134a vapor at 100°F is condensed at...Ch. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Is it possible to compress an ideal gas...Ch. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - A rigid tank contains 10 lbm of air at 30 psia and...Ch. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Air is contained in a variable-load...Ch. 5 - A mass of 15 kg of air in a piston–cylinder device...Ch. 5 - Prob. 70PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Air is contained in a cylinder device fitted with...Ch. 5 - Air is contained in a piston–cylinder device at...Ch. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 81PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Repeat Prob. 5–86 for aluminum balls.
5-86. In a...Ch. 5 - Prob. 88RQCh. 5 - Prob. 89RQCh. 5 - Air in the amount of 2 lbm is contained in a...Ch. 5 - Air is expanded in a polytropic process with n =...Ch. 5 - Nitrogen at 100 kPa and 25°C in a rigid vessel is...Ch. 5 - A well-insulated rigid vessel contains 3 kg of...Ch. 5 - In order to cool 1 ton of water at 20°C in an...Ch. 5 - Prob. 95RQCh. 5 - Prob. 96RQCh. 5 - Saturated water vapor at 200°C is condensed to a...Ch. 5 - A piston–cylinder device contains 0.8 kg of an...Ch. 5 - A piston–cylinder device contains helium gas...Ch. 5 - Prob. 100RQCh. 5 - Prob. 101RQCh. 5 - Prob. 102RQCh. 5 - Prob. 103RQCh. 5 - Prob. 104RQCh. 5 - Prob. 105RQCh. 5 - Prob. 106RQCh. 5 - A 68-kg man whose average body temperature is 39°C...Ch. 5 - An insulated rigid tank initially contains 1.4-kg...Ch. 5 - Prob. 109RQCh. 5 - Prob. 111RQCh. 5 - Prob. 112RQCh. 5 - Prob. 114RQCh. 5 - Prob. 115RQCh. 5 - An insulated piston–cylinder device initially...Ch. 5 - Prob. 118RQCh. 5 - Prob. 119RQCh. 5 - Prob. 120RQ
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- Procedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardFor each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forward
- The triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forward
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