
Concept explainers
Interpretation:
An alcohol from given alcohols, which is converted to the corresponding chloride at the fastest rate, on reaction with concentrated hydrochloric acid is to be determined. Which one reacts at the slowest rate is to be determined as well.
Concept Introduction:
The
When a tertiary alcohol reacts with hydrogen chloride, a tertiary carbocation is formed.
When a secondary alcohol reacts with hydrogen chloride, a secondary carbocation is formed.
When a primary alcohol reacts with hydrogen chloride, a primary carbocation is formed.
Tertiary alcohols react fastest while primary alcohols react the slowest on reaction with concentrated hydrochloric acid.
More stable carbocations are formed faster, than less stable carbocations. Thus, tertiary carbocations react the fastest, while primary carbocations react the slowest on reaction with concentrated hydrochloric acid.

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Chapter 5 Solutions
ORGANIC CHEMISTRY (LL)-W/SOLN.>CUSTOM<
- Propose a synthesis of 1-butanamine from the following: (a) a chloroalkane of three carbons (b) a chloroalkane of four carbonsarrow_forwardSelect the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forward
- b. H3C CH3 H3O+ ✓ H OHarrow_forward2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forward
- Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forwardInstructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
