The Force Exerted on the Moon In Figure 5-37 we show the Earth, Moon, and Sun (not to scale) in their relative positions at the time when the Moon is in its third-quarter phase. Though few people realize it, the force exerted on the Moon by the Sun is actually greater than the force exerted on the Moon by the Earth In fact, the force exerted on the Moon by the Sun has a magnitude of F SM = 4.34 × 10 20 N , whereas the force exerted by the Earth has a magnitude of only F EM = 1.98 × 10 20 N. These forces are indicated to scale in Figure 5-37 . Find (a) the direction and (b) the magnitude of the net force acting on the Moon. (c) Given that the mass of the Moon is M M = 7.35 × 10 22 kg , find the magnitude of its acceleration at the time of the third-quarter phase. Figure 5-37 Problems 35
The Force Exerted on the Moon In Figure 5-37 we show the Earth, Moon, and Sun (not to scale) in their relative positions at the time when the Moon is in its third-quarter phase. Though few people realize it, the force exerted on the Moon by the Sun is actually greater than the force exerted on the Moon by the Earth In fact, the force exerted on the Moon by the Sun has a magnitude of F SM = 4.34 × 10 20 N , whereas the force exerted by the Earth has a magnitude of only F EM = 1.98 × 10 20 N. These forces are indicated to scale in Figure 5-37 . Find (a) the direction and (b) the magnitude of the net force acting on the Moon. (c) Given that the mass of the Moon is M M = 7.35 × 10 22 kg , find the magnitude of its acceleration at the time of the third-quarter phase. Figure 5-37 Problems 35
The Force Exerted on the Moon In Figure 5-37 we show the Earth, Moon, and Sun (not to scale) in their relative positions at the time when the Moon is in its third-quarter phase. Though few people realize it, the force exerted on the Moon by the Sun is actually greater than the force exerted on the Moon by the Earth In fact, the force exerted on the Moon by the Sun has a magnitude of FSM = 4.34 × 1020N , whereas the force exerted by the Earth has a magnitude of only FEM = 1.98 × 1020N. These forces are indicated to scale in Figure 5-37. Find (a) the direction and (b) the magnitude of the net force acting on the Moon. (c) Given that the mass of the Moon is MM = 7.35 × 1022kg , find the magnitude of its acceleration at the time of the third-quarter phase.
Newton's universal law of gravitation states that every particle in the
universe attracts every other particle with a force along a line joining them.
The force is directly proportional to the product of their masses and
inversely proportional to the square of the distance between them.
Mathematically, it can be written as
GMm
F =
According to this law, when distance between two masses is reduced by half,
the force
becomes half compared to original
O becomes two times larger compared to original
becomes quarter of the original
becomes four times larger compared to original
55-56. Ganymede, one of Jupiter's moons, is the largest moon in our solar system. It has a mass of 1.48 × 1023 kg and a radius of 2.63 × 10 m. A 15.0 kg lunar rover is on Ganymede's surface.
55. As the rover orbits Ganymede, it is observed that during a particular segment of time, its speed decreases. During this segment of time, the work done by gravity on the rover is:
a positive
b) negative c zero
d) more info is needed to determine
56. Find Ganymede's escape speed (the minimum launch speed from Ganymede's surface such that the projectile never falls back).
a) 2.39 km/s
b) 2.74 km/s
c) 3.09 km/s
d) 3.44 km/s
e) 3.79 km/s
The gravitational force F→SM that the sun exerts on the moon is perpendicular to the force F→EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 × 1030 kg, mass of earth = 5.98 × 1024 kg, mass of moon = 7.35 × 1022 kg. The distances shown in the drawing are rSM = 1.50 × 1011 m and rEM = 3.85 × 108 m. Determine the magnitude of the net gravitational force on the moon.
Microbiology with Diseases by Body System (5th Edition)
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