Chapter 5, Problem 28CR

To determine

To find: The rate at which pool is being drained in milliliters per second from gallons per hour rounded to nearest tenth.

Answer to Problem 28CR

Therate at which pool is being drained in milliliters per second is $52.6\frac{\text{mL}}{\text{s}}$ .

Explanation of Solution

Given information: The rate of swimming pool being drained per hour is $50\text{gallons}$ .

Calculation:

The expression for swimming pool draining rate in ratio is:

  $\frac{50\text{gal}}{1\text{h}}$

The conversion of gallons per hourinto milliliters per houris:

  $1\frac{\text{gal}}{\text{h}}=3785\frac{\text{mL}}{\text{h}}$

To find the conversion of $\frac{50\text{gal}}{1\text{h}}$ , multiply both sides of above conversion by $\frac{50}{1}$ .

  $\begin{array}{c}\frac{50}{1}\times 1\frac{\text{gal}}{\text{h}}=\frac{50}{1}\times 3785\frac{\text{mL}}{\text{h}}\\ =189,250\frac{\text{mL}}{\text{h}}\end{array}$

The conversion of milliliters per hour into milliliters per second is:

  $1\frac{\text{mL}}{\text{h}}=\frac{1}{3600}\frac{\text{mL}}{\text{s}}$

To find the conversion of $189,250\frac{\text{mL}}{\text{h}}$ , multiply both sides of above conversion by $189,250$ .

  $\begin{array}{c}189,250\times 1\frac{\text{mL}}{\text{h}}=189,250\times \frac{1}{3600}\frac{\text{mL}}{\text{s}}\\ =52.569\frac{\text{mL}}{\text{s}}\\ \approx 52.6\frac{\text{mL}}{\text{s}}\end{array}$

Therefore, the rate at which swimming pool is being drained in milliliters per second is $52.6\frac{\text{mL}}{\text{s}}$ .