Chapter 5, Problem 34CR

To determine

To find: The cost paid for $40\text{party}\text{favors}$ and $60\text{party}\text{favors}$ at the same rate.

Answer to Problem 34CR

Thecost paid for $40\text{party}\text{favors}$ is $\$8.00$ and cost paid for $60\text{party}\text{favors}$ is $\$12.00$ .

Explanation of Solution

Given information: The cost paid by Mrs. Tebon for $25\text{party}\text{favors}$ is $\$5$ .

Calculation:

The expression of Proportional relationships in equation form is:

  $y=kx$

Here, constant of proportionality is $k$ .

To determine the value of $k$ , substitute $\$5$ for $y$ and $25$ for $x$ and in the above formula of proportional relationship.

  $\begin{array}{c}\$5=k\left(25\right)\\ k=\frac{\$5}{25}\\ =0.2\end{array}$

The constant of proportionality is $0.2$ . So, the cost is $0.2$ per party favor.

Let, the cost of party favor is $c$ and number of party favoris $r$ .

Substitute $c$ for $y$ , $r$ for $x$ and $0.2$ for $k$ in the equationof proportional relationship.

  $c=0.2r$

To determine the cost of $40\text{party}\text{favors}$ , substitute $40$ for $r$ in the above equation.

  $\begin{array}{c}c=0.2\left(40\right)\\ =8.00\end{array}$

To determine the cost of $60\text{party}\text{favors}$ , substitute $60$ for $r$ in the above equation of proportional relationship.

  $\begin{array}{c}c=0.2\left(60\right)\\ =12.00\end{array}$

Therefore, the cost paid for $40\text{party}\text{favors}$ is $\$8.00$ and cost paid for $60\text{party}\text{favors}$ is $\$12.00$ .