Explanation Given Information: The volume of liquid nitrogen is 1.0 L . The dimensions of the container is 1.0 m by 1.0 m by 2.0 m . The temperature of the gas is 25.0 ° C . The pressure of the gas is 1.0 atm . The density of liquid nitrogen is 0.807 g/mL . The conversion of temperature from ° C into Kelvin is done as, T K = T ° C + 273 K Hence, the conversion of temperature from 25.0 ° C into Kelvin is, T K = ( 25 + 273 ) K = 298 K The conversion of density from g/mL into g/L is done as, 1 g/mL = 10 3 g/L Hence, the conversion of density from 0.807 g/mL into g/L is, 1 g/mL = 0.807 × 10 3 g/L = 807 g/L The volume of container is calculated by multiplying its length breadth and height which is given as, Volume of container = 1.0 m × 1.0 m × 2.0 m = 2.0 m 3 The conversion of volume from m 3 into liter is done as, 1 m 3 = 1000 L Hence, the conversion of volume from 2.0 m 3 into liter is, 2.0 m 3 = 2.0 × 1000 L = 2000 L The mass of nitrogen gas present in the container is calculated by using the formula, Mass = Density × Volume Substitute the values of density and volume of liquid nitrogen in the above equation

Principles of Chemistry: A Molecular Approach (3rd Edition)

3rd Edition

ISBN: 9780321971944

Author: Nivaldo J. Tro

Publisher: PEARSON

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Question

Chapter 5, Problem 18E

Interpretation Introduction

Interpretation:

The percent volume of the air displaced by the evaporation of given amount of liquid nitrogen is to be calculated.
Concept Introduction: The percent volume of air displaced by the evaporation of gas is calculated by dividing the volume of nitrogen gas in the air by the volume of container and multiply with 100 .

To determine: The percent volume of the air displaced by the evaporation of given amount of liquid nitrogen.

Expert Solution & Answer

Chapter 5 Solutions

Principles of Chemistry: A Molecular Approach (3rd Edition)

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