Chapter 5, Problem 17Q

(a)

Interpretation Introduction

Interpretation:

The ionic compound name and the chemical formula that can be formed from $Na$ and $Cl$ has to be given.

Concept Introduction:

Ionic compound is formed from a metal and a non-metal.  Metal forms a cation while non-metal forms an anion.  Ionic compound is composed of ions present in fixed proportions.  They gave a regular geometric structure and are arranged in regular manner.

Ionic compounds are named in a way that the cation name is given first followed by the anion name with a space between cation name and anion name.  For the anion name, suffix “-ide” will be added.

Explanation of Solution

Given elements are $Na$ and $Br$.  In this sodium is a metal and bromine is a nonmetal.  Therefore, sodium forms the cation part while bromine forms that anion part.  Sodium belongs to Group IA and it has one valence electron.  Bromine belongs to Group VIIA and it has seven valence electrons.  Sodium loses the one valence electron and bromine gains one electron to attain octet configuration.  Hence, sodium and bromine can form ionic compound in 1:1 ratio.  Hence, the chemical formula of ionic compound is $NaCl$.

Name of $NaCl$ can be given by cation name followed by the anion name.  Therefore, the name of $NaCl$ can be given as sodium chloride.

Conclusion

Chemical formula and name of ionic compound that is formed from $Na$ and $Br$ is given.

(b)

Interpretation Introduction

Interpretation:

The ionic compound name and the chemical formula that can be formed from $Cd$ and $S$ has to be given.

Concept Introduction:

Ionic compound is formed from a metal and a non-metal.  Metal forms a cation while non-metal forms an anion.  Ionic compound is composed of ions present in fixed proportions.  They gave a regular geometric structure and are arranged in regular manner.

Ionic compounds are named in a way that the cation name is given first followed by the anion name with a space between cation name and anion name.  For the anion name, suffix “-ide” will be added.

Explanation of Solution

Given elements are $Cd$ and $S$.  In this cadmium is a metal and sulfur is a nonmetal.  Therefore, cadmium forms the cation part while sulfur forms that anion part.  Cadmium belongs to Group IIA and it has two valence electrons.  Sulfur belongs to Group VIA and it has six valence electrons.  Cadmium loses two valence electrons and sulfur gains two electrons to attain octet configuration.  Hence, cadmium and sulfur can form ionic compound in 1:1 ratio.  Hence, the chemical formula of ionic compound is $CdS$.

Name of $CdS$ can be given by cation name followed by the anion name.  Therefore, the name of $CdS$ can be given as cadmium sulfide.

Conclusion

Chemical formula and name of ionic compound that is formed from $Cd$ and $S$ is given.

(c)

Interpretation Introduction

Interpretation:

The ionic compound name and the chemical formula that can be formed from $Ba$ and $Cl$ has to be given.

Concept Introduction:

Ionic compound is formed from a metal and a non-metal.  Metal forms a cation while non-metal forms an anion.  Ionic compound is composed of ions present in fixed proportions.  They gave a regular geometric structure and are arranged in regular manner.

Ionic compounds are named in a way that the cation name is given first followed by the anion name with a space between cation name and anion name.  For the anion name, suffix “-ide” will be added.

Explanation of Solution

Given elements are $Ba$ and $Cl$.  In this barium is a metal and chlorine is a nonmetal.  Therefore, barium forms the cation part while chlorine forms that anion part.  Barium belongs to Group IIA and it has two valence electrons.  Chlorine belongs to Group VIIA and it has seven valence electrons.  Barium loses two valence electrons and chlorine gains one electron to attain octet configuration.  Hence, barium and chlorine can form ionic compound in 1:2 ratio.  Hence, the chemical formula of ionic compound is $BaC{l}_2$.

Name of $BaC{l}_2$ can be given by cation name followed by the anion name.  Therefore, the name of $BaC{l}_2$ can be given as barium chloride.

Conclusion

Chemical formula and name of ionic compound that is formed from $Ba$ and $Cl$ is given.

(d)

Interpretation Introduction

Interpretation:

The ionic compound name and the chemical formula that can be formed from $Al$ and $O$ has to be given.

Concept Introduction:

Ionic compound is formed from a metal and a non-metal.  Metal forms a cation while non-metal forms an anion.  Ionic compound is composed of ions present in fixed proportions.  They gave a regular geometric structure and are arranged in regular manner.

Ionic compounds are named in a way that the cation name is given first followed by the anion name with a space between cation name and anion name.  For the anion name, suffix “-ide” will be added.

Explanation of Solution

Given elements are $Al$ and $O$.  In this aluminium is a metal and oxygen is a nonmetal.  Therefore, aluminium forms the cation part while oxygen forms that anion part.  Aluminium belongs to Group IIIA and it has three valence electrons.  Oxygen belongs to Group VIA and it has six valence electrons.  Aluminium loses three valence electrons and oxygen gains two electrons to attain octet configuration.  Hence, aluminium and oxygen can form ionic compound in 2:3 ratio.  Hence, the chemical formula of ionic compound is $A{l}_2{O}_3$.

Name of $A{l}_2{O}_3$ can be given by cation name followed by the anion name.  Therefore, the name of $A{l}_2{O}_3$ can be given as aluminium oxide.

Conclusion

Chemical formula and name of ionic compound that is formed from $Al$ and $O$ is given.

(e)

Interpretation Introduction

Interpretation:

The ionic compound name and the chemical formula that can be formed from $Rb$ and $I$ has to be given.

Concept Introduction:

Ionic compound is formed from a metal and a non-metal.  Metal forms a cation while non-metal forms an anion.  Ionic compound is composed of ions present in fixed proportions.  They gave a regular geometric structure and are arranged in regular manner.

Ionic compounds are named in a way that the cation name is given first followed by the anion name with a space between cation name and anion name.  For the anion name, suffix “-ide” will be added.

Explanation of Solution

Given elements are $Rb$ and $I$.  In this rubidium is a metal and iodine is a nonmetal.  Therefore, rubidium forms the cation part while iodine forms that anion part.  Rubidium belongs to Group IA and it has one valence electron.  Iodine belongs to Group VIIA and it has seven valence electrons.  Rubidium loses the one valence electron and iodine gains one electron to attain octet configuration.  Hence, rubidium and iodine can form ionic compound in 1:1 ratio.  Hence, the chemical formula of ionic compound is $RbI$.

Name of $RbI$ can be given by cation name followed by the anion name.  Therefore, the name of $RbI$ can be given as rubidium iodide.

Conclusion

Chemical formula and name of ionic compound that is formed from $Rb$ and $I$ is given.