Chapter 5.5, Problem 5.13YT

(a)

Interpretation Introduction

Interpretation:

The concentration of ${\text{16ppb Hg}}^{\text{2+}}$ has to be expressed in units of molarity.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution.  The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$

(b)

Interpretation Introduction

Interpretation:

The number of moles of sodium chloride of $\text{1}\text{.5M}\text{and}\text{0}\text{.15M}$ in $\text{500mL}$ has to be calculated.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution.  The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$

(c)

Interpretation Introduction

Interpretation:

The solution that is more concentrated has to be determined.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution.  The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$

(d)

Interpretation Introduction

Interpretation:

The resulting solution prepared by student is $\text{2}\text{.0M}$ or not has to be determined.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution.  The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$