An organic compound contains carbon, hydrogen, and sulfur. A sample of it with a mass of 1.045 g was burned in oxygen to give gaseous CO 2 , H 2 O, and SO 2 . These gases were passed through 500.0 mL of an acidified 0.0200 M KMnO 4 solution, which caused the SO 2 to be oxidized to SO 4 2- . Only part of the available KMnO 4 was reduced to Mn 2+ . Next, 50.00 mL of 0.0300 M SnCl 2 was added to a 50.00 mL portion of this solution, which still contained unreduced KMnO 4 . There was more than enough added SnCl 2 to cause all of the remaining MnO 4 - in the 50 mL portion to be reduced to Mn 2+ . The excess Sn 2+ that still remained after the reaction was then titrated with 0.0100 M KMnO 4 , requiring 27.28 ml. of the KMnO 4 solution to reach the end point. What was the percentage of sulfur in the original sample of the organic compound that had been burned?
An organic compound contains carbon, hydrogen, and sulfur. A sample of it with a mass of 1.045 g was burned in oxygen to give gaseous CO 2 , H 2 O, and SO 2 . These gases were passed through 500.0 mL of an acidified 0.0200 M KMnO 4 solution, which caused the SO 2 to be oxidized to SO 4 2- . Only part of the available KMnO 4 was reduced to Mn 2+ . Next, 50.00 mL of 0.0300 M SnCl 2 was added to a 50.00 mL portion of this solution, which still contained unreduced KMnO 4 . There was more than enough added SnCl 2 to cause all of the remaining MnO 4 - in the 50 mL portion to be reduced to Mn 2+ . The excess Sn 2+ that still remained after the reaction was then titrated with 0.0100 M KMnO 4 , requiring 27.28 ml. of the KMnO 4 solution to reach the end point. What was the percentage of sulfur in the original sample of the organic compound that had been burned?
An organic compound contains carbon, hydrogen, and sulfur. A sample of it with a mass of 1.045 g was burned in oxygen to give gaseous
CO
2
, H
2
O, and SO
2
. These gases were passed through 500.0 mL of an acidified 0.0200 M
KMnO
4
solution, which caused the
SO
2
to be oxidized to
SO
4
2-
. Only part of the available
KMnO
4
was reduced to
Mn
2+
. Next, 50.00 mL of 0.0300 M
SnCl
2
was added to a 50.00 mL portion of this solution, which still contained unreduced
KMnO
4
. There was more than enough added
SnCl
2
to cause all of the remaining
MnO
4
-
in the 50 mL portion to be reduced to
Mn
2+
. The excess
Sn
2+
that still remained after the reaction was then titrated with 0.0100 M
KMnO
4
, requiring 27.28 ml. of the
KMnO
4
solution to reach the end point. What was the percentage of sulfur in the original sample of the organic compound that had been burned?
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell