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Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 5, Problem 11P
The recombination frequency between linked genes is less than
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Students have asked these similar questions
The recombination frequency in a cross can never exceed 50%. Explain why is this limit?
If 2 genes on the same chromosome have a recombination frequency of .01, what is the genetic distance from each other in map units?
Recombination frequency between two linked loci is always less than 0.5 (or 50%). Why?
Chapter 5 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 5 - For parts a, b, and c, draw a diagram illustrating...Ch. 5 - 5.2 In a diploid species of plant, the genes for...Ch. 5 - A pure-breeding tall plant producing oval fruit as...Ch. 5 - 5.4 Genes E and H are syntenic in an experimental...Ch. 5 - In tomato plants, purple leaf color is controlled...Ch. 5 - 5.6 In Drosophila, the map positions of genes are...Ch. 5 - 5.7 Genes A, B, and C are linked on a chromosome...Ch. 5 - Gene G recombines with gene T at a frequency of...Ch. 5 - Genes A, B, C, D, and E are linked on a...Ch. 5 - Syntenic genes can assort independently. Explain...
Ch. 5 - The recombination frequency between linked genes...Ch. 5 - On the DrosophilaX chromosome, the dominant allele...Ch. 5 - Researchers cross a corn plant that is pure -...Ch. 5 - 5.14 syndrome is an autosomal disorder affecting...Ch. 5 - 5.15 Three dominant traits of corn seedlings,...Ch. 5 - 5.16 In a diploid plant species, an with the...Ch. 5 - Prob. 17PCh. 5 - The Rh blood group in humans is determined by a...Ch. 5 - 5.19 Genetic linkage mapping for a large number of...Ch. 5 - 20. Neurospora with the genotype form tetrads in...Ch. 5 -
Gene and gene are genetically linked. Answer...Ch. 5 -
T. H. Morgan’s data on eye color and wing form,...Ch. 5 - Prob. 23PCh. 5 -
The boss in your laboratory has just heard of a...Ch. 5 - In rabbits, chocolate-colored fur (w+) is dominant...Ch. 5 - Prob. 26PCh. 5 - 5.27 In tomatoes, the allele for tall plant height...Ch. 5 - 5.28 Neurofibromatosis is an autosomal dominant...Ch. 5 - A 2006 genetic study of a large American family...Ch. 5 - 5.30 A experiment examining potential genetic...Ch. 5 - 31. As part of their analysis of intragenic...Ch. 5 - In experiments published in 1918 that sought to...
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- Instructions: — Please answer properly — Donot copy here in Bartleby or in Google.arrow_forwardResearchers have discovered that some regions of chromosomes are more likely than others to cross over, these areas of frequent crossing over are called "recombination hot spots". Gene A and B are 500,000 bp apart - the genes are either side of a recombination hot spot. Gene C and D are also 500,000 bp apart but the region containing genes C and D are not near a recombination hot spot. Would the map distance between A and B be the same as the map distance between C and D? Explain your answer.arrow_forwardDescribe two forms of genetic recombination. What functions do they fulfill?arrow_forward
- Now that you have counted the non-recombinant and recombinant asci we want to determine the recombination frequency between the tan gene and the centromere. To calculate the recombination frequency we need an accurate count of the number of non-recombinant recombinant individuals. In the asci the individuals are the ascospores. and 1118 WWW 4 non- recombinant ascospores 4 non- recombinant ascospores 1838 W M M M 500 2 non- recombinant ascospores 2 recombinant ascospores 2 recombinant ascospores 2 non- recombinant ascospores Figure 1.6. The number of ascospores in non-recombinant and recombinant asci. In the non-recombinant asci all 8 ascospores are non-recombinant (see Figure 1.6 above). In the non-recombinant asci 4 of the ascospores are recombinant and 4 of the ascospores are non-recombinant (see Figure 1.6 above). To determine how many recombinant and non-recombinant ascospores where in the two pictures above we need to do the math below. You need to use the total number of…arrow_forwardBelow are two pictures of perithecium on microscope slides that have been squished under cover slips so that the asci inside have spread out. In the asci, we can clearly see the tan ascospores (light colored) and wildtype ascospores (dark colored). We will perform our tetrad analysis by counting how many of the asci are non-recombinant and how many of the acsi are recombinant. We can tell which are recombinant and non-recombinant by observing the patterns of the ascospores in the asci. See the patterns of ascospores for non- recombinant and recombinant asci in the table below. Ascospore pattern of non-recombinant asci OOOO OOOOO You will count the total number of non-recombinant and recombinant asci in the two pictures below. You will only count the asci that have a star next to them because these asci can be clearly identified as non-recombinant or recombinant. Select the correct number below after you are done. Total number of non-recombinant asci [Select] Ascospore pattern of…arrow_forwardEukaryotic cells can repair DNA through a process called homologous recombination. What type of DNA damage can be fixed through homologous recombination?arrow_forward
- Researchers have discovered that some regions of chromosomes are more likely than others to cross over, these areas of frequent crossing over are called "recombination hot spots". Gene A and B are 500,000 bp apart - both genes and the space between them are in a recombination hot spot. Gene C and D are also 500,000 bp apart but the region containing genes C and D are not a recombination hot spot. Would the map distance between A and B be the same as the map distance between C and D? Explain your answer.arrow_forwardBased on the attached image, if we are using the Holliday junction model of recombination, where exactly would be the positions where DNA is cut? Would it be to the right because of branch migration?arrow_forwardDNA obtalned from the indicated donor strains is used to TRANSFORM the indicated recipient strains. The resulting progeny are plated on minimal medium so that only wild- type recombinants are scored. The number of wild-types for each cross is given in the chart below. What is the order of the genes? Donor Recipient wid type colonies a-b- c+ a+ b+ c- 273 a- b+ c- a+ b-c+ 462 a- b+ C+ a+ b-c- 2 a b- C+ a- b+ c+ O 4-b-c a-o-b b-a-c cannot be determined Question 18 of 26arrow_forward
- a) Are the genes linked? Please explain SPECIFICALLY how you can distinguish between linked and unlinked genes in this instance. b) If the two genes are linked, calculate the % recombination between ser and thr. Show the formula used, as well as all of your calculations. c) Draw a single map illustrating the arrangement of the two genes on the chromosome with respect to each other and to the centromere of the chromosome. Make sure to map ALL three distances.arrow_forwardIn the Holliday model for homologous recombination shown, the resolution steps can produce recombinant or nonrecombinantchromosomes. Explain how this can occur.arrow_forwardThe presence (+) or absence (−) of six sequences in each of five bacterial artificial chromosome (BAC) clones (A–E) is indicated in the following table. Using these markers, put the BAC clones in their correct order and indicate the locations of the numbered sequences within them. Sequences BAC clone 1 2 3 4 5 6 A + − − − + − B − − − + − + C − + + − − − D − − + − + − E + − − + − −arrow_forward
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license