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Chapter 4 Solutions
Elementary Geometry for College Students
- Direction: Strictly write in 4 bond paper, because my activity sheet is have 4 spaces. This is actually for maritime. industry course, but I think geometry can do this. use nautical almanac. Sample Calculation (Amplitude- Sun): On 07th May 2006 at Sunset, a vesel in position 10°00'N 0 10°00' W observed the sun bearing 288° by compass. Find the compass error. LMT Sunset 07d 18h 13m (+)00d 00h 40 м LIT: UTC Sunset: 07d 18h 53 m added - since longitude is westerly Declination Co7d 18h): N016° 55.5' d(0.7): (+) 00-6 N016 56.1' Declination Sun: Sin Amplitude Sin Declination (Los Latitude - Sin 016° 56.1'/Cos 10°00' = 0.295780189 Amplitude = WI. 2N (The prefix of amplitude is named easterly if body is rising. and westerly of body is setting. The suffix is named came as declination.) True Bearing: 287.20 Compass Bearing 288.0° Compass Error: 0.8' Westarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk maths expert solve itarrow_forwardSuggest to geometry subject expertsarrow_forward
- Strick handwritten solutions needarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk Geometry expert solve itarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk Geometry expert solve itarrow_forward
- Only 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk Geometry expert solve itarrow_forwardMinimum number of times that activity should be recorded: 9 (3 each phase) Sample calculation (Azimuth- Stars): On 05th May 2006 at 11h00m00s UTC, a vessel in position 04°30'N 010°00'W observed Canopus bearing 145° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Aries (05d 11h): 028° 10.7' Increment (00m 00s): 000° 00.0' GHA Aries: 028° 10.7' Longitude (W): (-) 010° 00.0' (minus- since longitude is westerly) LHA Aries: 018° 10.7' SHA Canopus: (+) 263° 59.0' LHA Canopus: 282° 09.7' S 052° 42.1' Declination: P=360-282° 09.7'= 77° 50.3' (If LHA>180°, P= 360-LHA) A Tan Latitude/ Tan P A Tan 04° 30' Tan 77° 50.3' A = 0.016960803 S (A is named opposite to latitude, except when hour angle is between 090° and 270°) B=Tan Declination/ Sin P B= Tan 052° 42.1/ Sin 77° 50.3' B=1.342905601 S (B is always named same as declination) C=A+B=1.359866404 S (C correction, A+/- B: If A and B have same name- add, If different name- subtract) Tan Azimuth 1/ (CX…arrow_forward3) roadway Calculate the overall length of the conduit run sketched below. 2' Radius 8' 122-62 Sin 30° = 6/H 1309 16.4%. 12' H= 6/s in 30° Year 2 Exercise Book Page 4 10 10 10 fx-300MS S-V.PA Topic 1arrow_forward
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