Direction: Strictly write this in 5 bondpaper, because my activity book have 5 spaces. This is actually for maritime industry course, but I think Geometry can do this. Use nautical almanac. Task number: A 1.1, A1.7 TOPIC/ Celestial Navigation, Compass - Magnetic and Gyro [Activity : Determine compass ervor (magnetic and gyro) using azimuth-chasing a suitable celestial body (Sun/Stars | Planets / Mon). Apply variation to Find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 9 (3 each phase) Sample calculation (Azimuth- Stars): On 05th May 2006 at 11h00m00s UTC, a vessel in position 04°30'N 010°00'W observed Canopus bearing 145° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Aries (05d 11h): 028° 10.7' Increment (00m 00s): 000° 00.0' GHA Aries: 028° 10.7' Longitude (W): (-) 010° 00.0' (minus- since longitude is westerly) LHA Aries: 018° 10.7' SHA Canopus: (+) 263° 59.0' LHA Canopus: 282° 09.7' S 052° 42.1' Declination: P=360-282° 09.7'= 77° 50.3' (If LHA>180°, P= 360-LHA) A Tan Latitude/ Tan P A Tan 04° 30' Tan 77° 50.3' A = 0.016960803 S (A is named opposite to latitude, except when hour angle is between 090° and 270°) B=Tan Declination/ Sin P B= Tan 052° 42.1/ Sin 77° 50.3' B=1.342905601 S (B is always named same as declination) C=A+B=1.359866404 S (C correction, A+/- B: If A and B have same name- add, If different name- subtract) Tan Azimuth 1/ (CX Cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E (Azimuth takes combined name of C correction and Hour Angle- If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east") True Azimuth=143.6° Compass Azimuth= 145.0° Compass Error = 1.4° West Variation 4.0° East Deviation 5.4° West

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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Direction: Strictly write this in 5 bondpaper, because my activity book
have 5 spaces. This is actually for maritime industry course, but
I think Geometry can do this. Use nautical almanac.
Task number: A 1.1, A1.7
TOPIC/ Celestial Navigation, Compass - Magnetic and Gyro
[Activity : Determine compass ervor (magnetic and gyro) using azimuth-chasing
a suitable celestial body (Sun/Stars | Planets / Mon). Apply variation
to Find the deviation of the magnetic compass.
Transcribed Image Text:Direction: Strictly write this in 5 bondpaper, because my activity book have 5 spaces. This is actually for maritime industry course, but I think Geometry can do this. Use nautical almanac. Task number: A 1.1, A1.7 TOPIC/ Celestial Navigation, Compass - Magnetic and Gyro [Activity : Determine compass ervor (magnetic and gyro) using azimuth-chasing a suitable celestial body (Sun/Stars | Planets / Mon). Apply variation to Find the deviation of the magnetic compass.
Minimum number of times that activity should be recorded: 9 (3 each phase)
Sample calculation (Azimuth- Stars):
On 05th May 2006 at 11h00m00s UTC, a vessel in position 04°30'N 010°00'W observed Canopus
bearing 145° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation.
GHA Aries (05d 11h):
028° 10.7'
Increment (00m 00s):
000° 00.0'
GHA Aries:
028° 10.7'
Longitude (W):
(-)
010° 00.0' (minus- since longitude is westerly)
LHA Aries:
018° 10.7'
SHA Canopus:
(+)
263° 59.0'
LHA Canopus:
282° 09.7'
S 052° 42.1'
Declination:
P=360-282° 09.7'= 77° 50.3' (If LHA>180°, P= 360-LHA)
A Tan Latitude/ Tan P
A Tan 04° 30' Tan 77° 50.3'
A = 0.016960803 S (A is named opposite to latitude, except when hour angle is between 090° and
270°)
B=Tan Declination/ Sin P
B= Tan 052° 42.1/ Sin 77° 50.3'
B=1.342905601 S (B is always named same as declination)
C=A+B=1.359866404 S (C correction, A+/- B: If A and B have same name- add, If different name-
subtract)
Tan Azimuth 1/ (CX Cos Latitude)
Tan Azimuth = 0.737640253
Azimuth = S 36.4° E (Azimuth takes combined name of C correction and Hour Angle- If LHA is
between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east")
True Azimuth=143.6°
Compass Azimuth= 145.0°
Compass Error = 1.4° West
Variation 4.0° East
Deviation 5.4° West
Transcribed Image Text:Minimum number of times that activity should be recorded: 9 (3 each phase) Sample calculation (Azimuth- Stars): On 05th May 2006 at 11h00m00s UTC, a vessel in position 04°30'N 010°00'W observed Canopus bearing 145° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Aries (05d 11h): 028° 10.7' Increment (00m 00s): 000° 00.0' GHA Aries: 028° 10.7' Longitude (W): (-) 010° 00.0' (minus- since longitude is westerly) LHA Aries: 018° 10.7' SHA Canopus: (+) 263° 59.0' LHA Canopus: 282° 09.7' S 052° 42.1' Declination: P=360-282° 09.7'= 77° 50.3' (If LHA>180°, P= 360-LHA) A Tan Latitude/ Tan P A Tan 04° 30' Tan 77° 50.3' A = 0.016960803 S (A is named opposite to latitude, except when hour angle is between 090° and 270°) B=Tan Declination/ Sin P B= Tan 052° 42.1/ Sin 77° 50.3' B=1.342905601 S (B is always named same as declination) C=A+B=1.359866404 S (C correction, A+/- B: If A and B have same name- add, If different name- subtract) Tan Azimuth 1/ (CX Cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E (Azimuth takes combined name of C correction and Hour Angle- If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east") True Azimuth=143.6° Compass Azimuth= 145.0° Compass Error = 1.4° West Variation 4.0° East Deviation 5.4° West
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