Direction: Strictly write this in 4 bondpaper, because my activity book have 4 spaces. This is actually for maritime industry course, but I think creometry can do this. Use nautical almanac. Task number: A1.1, A1.7 TOPIC/ Celestial Navigation, Compass - Magnetic and Gyro Activity: Determine compass ervor (magnetic and gyro) using azimuth-chasing a suitable celestial budy (Sun/Stars / Planets/Moon). Apply variation to find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 9 (3 each phase) Sample calculation (Azimuth- Sun): On 09th May 2006 at 05h30m00s UTC, a vessel in position 55°00'N 002°00'W observed the Sun bearing 073° by magnetic compass. Find the compass error. If variation is 5°W, calculate the deviation. GHA Sun (09d 05h): Increment (30m00s): GHA Sun: Longitude (W): LHA Sun: 255° 53.2' 007° 30.0° 263° 23.2' (-) 002° 00.0' (minus- since longitude is westerly) (+) 261°23.2' N 017° 19.2 inulit ko yung una, hindi 00.4' N 017° 19.6' kasi naka allow replay yon eh Declination (09d 05h): d (0.7): Declination Sun: P 360-261° 23.2'= 98° 36.8' (If LHA>180°, P= 360-LHA) A Tan Latitude/Tan P A Tan 55° 00% Tan 98° 36.8' A=0.216327037 N (A is named opposite to latitude, except when hour angle is between 090° and 270°) B=Tan Declination/ Sin P B= Tan 017° 19.6'/ Sin 98° 36.8' B=0.315534702 N (B is always named same as declination) C=A+B = 0.531861739 N (C correction, A+/- B: If A and B have same name- add, If different name- subtract) Tan Azimuth=1/(CX Cos Latitude) Tan Azimuth = 3.278007549 Azimuth N 73.0° E (Azimuth takes combined name of C correction and Hour Angle- If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east") True Azimuth= 73.0° Compass Azimuth=73.0° Compass Error = NIL Variation=5.0° West Deviation=5.0° East

Intermediate Algebra
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ISBN:9780998625720
Author:Lynn Marecek
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Chapter10: Exponential And Logarithmic Functions
Section10.3: Evaluate And Graph Logarithmic Functions
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Direction: Strictly write this in 4 bondpaper, because my activity book
have 4 spaces. This is actually for maritime industry course, but
I think creometry can do this. Use nautical almanac.
Task number: A1.1, A1.7
TOPIC/ Celestial Navigation, Compass - Magnetic and Gyro
Activity: Determine compass ervor (magnetic and gyro) using azimuth-chasing
a suitable celestial budy (Sun/Stars / Planets/Moon). Apply variation
to find the deviation of the magnetic compass.
Transcribed Image Text:Direction: Strictly write this in 4 bondpaper, because my activity book have 4 spaces. This is actually for maritime industry course, but I think creometry can do this. Use nautical almanac. Task number: A1.1, A1.7 TOPIC/ Celestial Navigation, Compass - Magnetic and Gyro Activity: Determine compass ervor (magnetic and gyro) using azimuth-chasing a suitable celestial budy (Sun/Stars / Planets/Moon). Apply variation to find the deviation of the magnetic compass.
Minimum number of times that activity should be recorded: 9 (3 each phase)
Sample calculation (Azimuth- Sun):
On 09th May 2006 at 05h30m00s UTC, a vessel in position 55°00'N 002°00'W observed the Sun
bearing 073° by magnetic compass. Find the compass error. If variation is 5°W, calculate the
deviation.
GHA Sun (09d 05h):
Increment (30m00s):
GHA Sun:
Longitude (W):
LHA Sun:
255° 53.2'
007° 30.0°
263° 23.2'
(-) 002° 00.0' (minus- since longitude is westerly)
(+)
261°23.2'
N 017° 19.2 inulit ko yung una, hindi
00.4'
N 017° 19.6'
kasi naka allow replay
yon eh
Declination (09d 05h):
d (0.7):
Declination Sun:
P 360-261° 23.2'= 98° 36.8' (If LHA>180°, P= 360-LHA)
A Tan Latitude/Tan P
A Tan 55° 00% Tan 98° 36.8'
A=0.216327037 N (A is named opposite to latitude, except when hour angle is between 090° and
270°)
B=Tan Declination/ Sin P
B= Tan 017° 19.6'/ Sin 98° 36.8'
B=0.315534702 N (B is always named same as declination)
C=A+B = 0.531861739 N (C correction, A+/- B: If A and B have same name- add, If different name-
subtract)
Tan Azimuth=1/(CX Cos Latitude)
Tan Azimuth = 3.278007549
Azimuth N 73.0° E (Azimuth takes combined name of C correction and Hour Angle- If LHA is
between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east")
True Azimuth= 73.0°
Compass Azimuth=73.0°
Compass Error = NIL
Variation=5.0° West
Deviation=5.0° East
Transcribed Image Text:Minimum number of times that activity should be recorded: 9 (3 each phase) Sample calculation (Azimuth- Sun): On 09th May 2006 at 05h30m00s UTC, a vessel in position 55°00'N 002°00'W observed the Sun bearing 073° by magnetic compass. Find the compass error. If variation is 5°W, calculate the deviation. GHA Sun (09d 05h): Increment (30m00s): GHA Sun: Longitude (W): LHA Sun: 255° 53.2' 007° 30.0° 263° 23.2' (-) 002° 00.0' (minus- since longitude is westerly) (+) 261°23.2' N 017° 19.2 inulit ko yung una, hindi 00.4' N 017° 19.6' kasi naka allow replay yon eh Declination (09d 05h): d (0.7): Declination Sun: P 360-261° 23.2'= 98° 36.8' (If LHA>180°, P= 360-LHA) A Tan Latitude/Tan P A Tan 55° 00% Tan 98° 36.8' A=0.216327037 N (A is named opposite to latitude, except when hour angle is between 090° and 270°) B=Tan Declination/ Sin P B= Tan 017° 19.6'/ Sin 98° 36.8' B=0.315534702 N (B is always named same as declination) C=A+B = 0.531861739 N (C correction, A+/- B: If A and B have same name- add, If different name- subtract) Tan Azimuth=1/(CX Cos Latitude) Tan Azimuth = 3.278007549 Azimuth N 73.0° E (Azimuth takes combined name of C correction and Hour Angle- If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east") True Azimuth= 73.0° Compass Azimuth=73.0° Compass Error = NIL Variation=5.0° West Deviation=5.0° East
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