Chapter 4.7, Problem 6CE

a.

To determine

A median of $\Delta ABC$ in the given figure.

Answer to Problem 6CE

BE is the median of $\Delta ABC$

Explanation of Solution

Given:

The given figure is,

  

Median: It divide the triangle into two equal triangles and a side into two equal sides.

From the given figure in $\Delta ABC$

BE divides AC into equal parts AE and EC.

So,

BE is the median of $\Delta ABC$

b.

To determine

An altitude of $\Delta ABC$ in the given figure.

Answer to Problem 6CE

AD is an altitude of $\Delta ABC$

Explanation of Solution

Given:

The given figure is,

  

An altitude is a line that makes an angle of 90 degrees with the side of a triangle.

From the given figure,

In $\Delta ABC$ , AD is perpendicular on BC.

So,

AD is an altitude of $\Delta ABC$

c.

To determine

Answer to Problem 6CE

CF is angle bisector in $\Delta ABC$

Explanation of Solution

Given:

The given figure is,

  

An angle bisector is a line that divides an angle into two equal parts.

From the given figure,

In $\Delta ABC$ , CF dives the angles $\angle ACF\text{and }\angle BCF$ into two equal parts.

So,

CF is angle bisector in $\Delta ABC$