Chapter 4.4, Problem 3WE

To determine

Value of x in the given figure.

Answer to Problem 3WE

Value of $x={53}^o$

Explanation of Solution

Given:

The given figure is,

  

From the given figure,

Side $AB=AC=10,\angle BAC={74}^o$ and $\angle BCA=x$

So, the given triangle is isosceles triangle.

So, $\angle ABC=\angle ACB=x$

Therefore,

  $\begin{array}{l}\angle ABC+ACB+\angle BAC={180}^o\\ x+x+{74}^o={180}^o\\ \Rightarrow x={53}^o\end{array}$

Therefore, $x={53}^o$