Explanation Write the expression for the energy balance equation for closed system. E i n − E o u t = Δ E s y s t e m (I) Here, energy transfer in to the system is E i n , energy transfer from the system is E o u t and change in internal energy of system is Δ E s y s t e m . Substitute 0 for E i n , Q o u t for E o u t and Δ U for Δ E s y s t e m . − Q o u t = Δ U (II) Here, amount of heat transfer exit from the system is Q o u t and change in internal energy is Δ U . Substitute m ( u 2 − u 1 ) for Δ U in Equation (II). − Q o u t = m ( u 2 − u 1 ) ≅ m c p ( T 2 − T 1 ) (III) Here, mass of system is m , specific heat at constant pressure is c p , initial temperature is T 1 and final temperature is T 2 . Calculate the mass of aluminum ( m ) ball. m = ρ π D 3 6 (IV) Here, density of aluminum is ρ and sphere diameter is D . Calculate the total rate of heat transfer ( Q ˙ t o t a l ) from aluminum ball into water. Q ˙ t o t a l = n ˙ b a l l Q i n (V) Here, rate of brass balls quenched in water bath is n ˙ b a l l . Conclusion: Refer to Table A-3, “properties of common liquids, solids, and foods”, obtain the following properties of Aluminum at the temperature of 370 K. c p = 0.937 kJ / kg ⋅ ° C ρ = 2 , 700 kg / m 3 Substitute 2 , 700 kg / m 3 for ρ and 0

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It is generally related to thermal engineering which tells about the use, creation, conversion and transfer of heat energy between the systems. It is also considered that to transfer heat from one source to another, transfer of masses is also required. T…

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Chapter 4.5, Problem 89P

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The total rate of heat transfer (Q˙total) from aluminum ball to water

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Chapter 4.5, Problem 88P

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The total rate of heat transfer ( Q ˙ t o t a l ) from aluminum ball to water

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