Chapter 4.5, Problem 15PPS

To determine

To solve and check: the given equation

Answer to Problem 15PPS

The required solution is $b=4$

Explanation of Solution

Given: $3b+15=27$

Calculation:

To solve equation and check the solution

  $3b+15=27$

Add both sides of equation with $-15$

  $\begin{array}{l}3b+15-15=27-15\\ 3b=12\end{array}$

Divide both sides of equation by $3$

  $\begin{array}{l}b=\frac{12}{3}\\ b=4\end{array}$

Solution:- $b=4$

Check

Substitute $b=4$ in $3b+15=27$

  $\begin{array}{l}3(4)+15=27\\ 12+15=27\\ 27=27\end{array}$

Hence verified .So solution is $b=4$ .

Conclusion:

Therefore, the required solution is $b=4$