Chapter 4.6, Problem 19PPS

(a)

To determine

To calculate:Towrite a set of ordered pairs for the data

Answer to Problem 19PPS

Set of ordered pairs is

  $\left(0,14.7\right),\left(1,10.2\right),\left(2,6.4\right),\left(3,4.3\right)\left(4,2.7\right),\left(5,1.6\right)$

Explanation of Solution

Given information:The air pressure decreases as the distance from Earth increases. Table showing the air pressure for certain distance

Height (mi)	Pressure (lb/in2)
0 (sea level)	14.7
1	10.2
2	6.4
3	4.3
4	2.7
5	1.6

Calculation:

Table is given as

Height (mi)	Pressure (lb/in2)
0 (sea level)	14.7
1	10.2
2	6.4
3	4.3
4	2.7
5	1.6

Set of ordered pairs are as follows:

  $\left(0,14.7\right)$

  $\left(1,10.2\right)$

  $\left(2,6.4\right)$

  $\left(3,4.3\right)$

  $\left(4,2.7\right)$

  $\left(5,1.6\right)$

(b)

To determine

To calculate: Tograph the data

Answer to Problem 19PPS

Set of ordered pairs is

  $\left(0,14.7\right),\left(1,10.2\right),\left(2,6.4\right),\left(3,4.3\right)\left(4,2.7\right),\left(5,1.6\right)$

Explanation of Solution

Given information:The air pressure decreases as the distance from Earth increases. Table showing the air pressure for certain distance

Height (mi)	Pressure (lb/in2)
0 (sea level)	14.7
1	10.2
2	6.4
3	4.3
4	2.7
5	1.6

Calculation:

On plotting the above points,

(c)

To determine

To calculate: Tostate domain and range.

Answer to Problem 19PPS

Domain is $\left\{0,1,2,3,4,5\right\}$

Range is $\left\{14.7,10.2,6.4,4.3,2.7,1.6\right\}$

Explanation of Solution

Given information:The air pressure decreases as the distance from Earth increases. Table showing the air pressure for certain distance

Height (mi)	Pressure (lb/in2)
0 (sea level)	14.7
1	10.2
2	6.4
3	4.3
4	2.7
5	1.6

Calculation:

Table is given as

Height (mi)	Pressure (lb/in2)
0 (sea level)	14.7
1	10.2
2	6.4
3	4.3
4	2.7
5	1.6

Domain is $\left\{0,1,2,3,4,5\right\}$

Range is $\left\{14.7,10.2,6.4,4.3,2.7,1.6\right\}$