Biology
Biology
10th Edition
ISBN: 9780321794260
Author: Audesirk, Teresa/ Audesirk
Publisher: Pearson College Div
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Chapter 44.2, Problem 1CYL
Summary Introduction

To draw:

The structure of a complete flower. Also, to explain the function of each part.

Introduction:

A flower is the reproductive part of an angiospermic plant. Flowers consist of many parts; sepals, petals, pedicel, thalamus, androecium (male reproductive part), and gynoecium (female reproductive part). Some flowers contain both male and female reproductive parts and are bisexual or monoecious. Some flowers contain either male or female reproductive part and are considered dioecious.

Summary Introduction

To describe:

The development of male and female gametophytes in flowering plants.

Introduction:

Angiosperms are vascular flowering plants. There are about 300,000 species of angiosperms. It is the most diverse group in kingdom Plantae. 80% of the total living green plants belong to angiosperms. Double fertilization is the characteristic feature of angiospermic plants.

Summary Introduction

To explain:

The processes of pollination and double fertilization.

Introduction:

Pollination is the process of transfer of pollen grains (male gametophyte) from another of the stamen to the stigma of the carpel. Pollination is of two types; self-pollination and cross-pollination. Pollination is required in plants for fertilization to take place.

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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin
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