Chapter 4.4, Problem 4.14YT

(a)

Interpretation Introduction

Interpretation:

The mass of S atoms in $\text{1}\text{.9}\text{×}{\text{10}}^{\text{7}}\text{t}$ (19 million metric ton) ${\text{SO}}_{\text{2}}$ has to be calculated.

Concept Introduction:

Molar mass of a substance is the mass in grams of one mole of the substance. Unit of molar mass is g/mol.

Molar mass of $H_{2}O$ can be determined as follows,

$\text{Molar}\text{mass}\text{of}{\text{H}}_{\text{2}}\text{O}=\underset{MassoftwoHydrogen}{\left(\text{2}\text{×}\text{1}\text{g}\right)}\text{+}\underset{massofoneOxygen}{\left(\text{1×}\text{16}\text{g}\right)}=18g/mol$

Mass ratio of a compound with formula AB can be determined as follows,

$\boxed{\text{Mass}\text{ratio}\text{of}\text{A}=\text{100}\text{.0}\text{g}\text{AB}\text{×}\frac{\text{Mass}\text{of}\text{A}}{\text{Mass}\text{of}\text{AB}}}$

(b)

Interpretation Introduction

Interpretation:

The mass of S atoms in $\text{1}\text{.42}\text{×}{\text{10}}^8\text{t}$${\text{SO}}_{\text{2}}$ has to be calculated.

Concept Introduction:

Molar mass of a substance is the mass in grams of one mole of the substance. Unit of molar mass is g/mol.

Molar mass of $H_{2}O$ can be determined as follows,

$\text{Molar}\text{mass}\text{of}{\text{H}}_{\text{2}}\text{O}=\underset{MassoftwoHydrogen}{\left(\text{2}\text{×}\text{1}\text{g}\right)}\text{+}\underset{massofoneOxygen}{\left(\text{1×}\text{16}\text{g}\right)}=18g/mol$

Mass ratio of a compound with formula AB can be determined as follows,

$\boxed{\text{Mass}\text{ratio}\text{of}\text{A}=\text{100}\text{.0}\text{g}\text{AB}\text{×}\frac{\text{Mass}\text{of}\text{A}}{\text{Mass}\text{of}\text{AB}}}$