Circle A, with radius a, and circle B , with radius b , are tangent to each other and to P Q ¯ (see figure). P R ¯ passes through the center of each circle. Let x be the distance from point P to a point S where P R ¯ intersects circle A on the left. Let θ denote ∠ R P Q . a. Show that sin θ = a x + a and sin θ = b x + 2 a + b . b. Use the results from part (a) to show that sin θ = b − a b + a .
Circle A, with radius a, and circle B , with radius b , are tangent to each other and to P Q ¯ (see figure). P R ¯ passes through the center of each circle. Let x be the distance from point P to a point S where P R ¯ intersects circle A on the left. Let θ denote ∠ R P Q . a. Show that sin θ = a x + a and sin θ = b x + 2 a + b . b. Use the results from part (a) to show that sin θ = b − a b + a .
Solution Summary: The author proves the following values of the trigonometric function, using the given figure.
Circle A, with radius a, and circle
B
, with radius
b
, are tangent to each other and to
P
Q
¯
(see figure).
P
R
¯
passes through the center of each circle. Let
x
be the distance from point
P
to a point
S
where
P
R
¯
intersects circle
A
on the left. Let
θ
denote
∠
R
P
Q
.
a. Show that
sin
θ
=
a
x
+
a
and
sin
θ
=
b
x
+
2
a
+
b
.
b. Use the results from part (a) to show that
sin
θ
=
b
−
a
b
+
a
.
Use the information to find and compare Δy and dy. (Round your answers to four decimal places.)
y = x4 + 7 x = −3 Δx = dx = 0.01
Δy =
dy =
4. A car travels in a straight line for one hour. Its velocity, v, in miles per hour at six minute intervals is shown
in the table. For each problem, approximate the distance the car traveled (in miles) using the given method,
on the provided interval, and with the given number of rectangles or trapezoids, n.
Time (min) 0 6 12 18|24|30|36|42|48|54|60
Speed (mph) 0 10 20 40 60 50 40 30 40 40 65
a.) Left Rectangles, [0, 30] n=5
b.) Right Rectangles, [24, 42] n=3
c.) Midpoint Rectangles, [24, 60] n=3
d.) Trapezoids, [0, 24] n=4
The bracket BCD is hinged at C and attached to a control cable at B. Let F₁ = 275 N and F2 = 275 N.
F1
B
a=0.18 m
C
A
0.4 m
-0.4 m-
0.24 m
Determine the reaction at C.
The reaction at C
N Z
F2
D
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