The accompanying figure shows the graph of the derivative of a function h that is defined and continuous on the interval − ∞ , + ∞ . Assume that the graph of h ′ has a vertical asymptote at x = 3 and that h ′ x → 0 + as x → − ∞ h ′ x → − ∞ as x → + ∞ (a) What are the critical points for h x ? (b) Identify the intervals on which h x is increasing. (c) Identify the x -coordinates of relative extrema for h x and classify each as a relative maximum or relative minimum. (d) Estimate the x -coordinates of inflection points for h x .
The accompanying figure shows the graph of the derivative of a function h that is defined and continuous on the interval − ∞ , + ∞ . Assume that the graph of h ′ has a vertical asymptote at x = 3 and that h ′ x → 0 + as x → − ∞ h ′ x → − ∞ as x → + ∞ (a) What are the critical points for h x ? (b) Identify the intervals on which h x is increasing. (c) Identify the x -coordinates of relative extrema for h x and classify each as a relative maximum or relative minimum. (d) Estimate the x -coordinates of inflection points for h x .
The accompanying figure shows the graph of the derivative of a function
h
that is defined and continuous on the interval
−
∞
,
+
∞
. Assume that the graph of
h
′
has a vertical asymptote at
x
=
3
and that
h
′
x
→
0
+
as
x
→
−
∞
h
′
x
→
−
∞
as
x
→
+
∞
(a) What are the critical points for
h
x
?
(b) Identify the intervals on which
h
x
is increasing.
(c) Identify the x-coordinates of relative extrema for
h
x
and classify each as a relative maximum or relative minimum.
(d) Estimate the x-coordinates of inflection points for
h
x
.
Formula Formula A function f(x) attains a local maximum at x=a , if there exists a neighborhood (a−δ,a+δ) of a such that, f(x)<f(a), ∀ x∈(a−δ,a+δ),x≠a f(x)−f(a)<0, ∀ x∈(a−δ,a+δ),x≠a In such case, f(a) attains a local maximum value f(x) at x=a .
For each given function f(x) find f'(x) using the rules learned in section 9.5.
1. f(x)=x32
32x
2. f(x)=7x+13
3. f(x) =
x4
4. f(x) = √√x³
5. f(x) = 3x²+
3
x2
Find:
lim x →-6 f (x)
limx-4 f (x)
lim x-1 f (x)
lim x →4 f (x)
(-6,3) •
(-1,5)
-8
-7
(-6,-2)
4+
(4,5)
(4,2) •
(-1,1)
-6
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