( RLC circuit ) The circuit in the figure consists of a resistor ( R ohms), an inductor ( L henrys), a capacitor ( C farads), and an initial voltage source. Let b = R /(2 L ), and suppose R , L , and C have been selected so that b also equals 1 / LC . (This is done, for instance, when the circuit is used in a voltmeter.) Let v ( t ) be the voltage (in volts) at time t , measured across the capacitor. It can be shown that v is in the null space H of the linear transformation that maps v ( t ) into Lv" ( t ) + Rv' ( t ) + (l/ C ) v ( t ), and H consists of all functions of the form v ( t ) = e − bt ( c 1 + c 2 t ). Find a basis for H .
( RLC circuit ) The circuit in the figure consists of a resistor ( R ohms), an inductor ( L henrys), a capacitor ( C farads), and an initial voltage source. Let b = R /(2 L ), and suppose R , L , and C have been selected so that b also equals 1 / LC . (This is done, for instance, when the circuit is used in a voltmeter.) Let v ( t ) be the voltage (in volts) at time t , measured across the capacitor. It can be shown that v is in the null space H of the linear transformation that maps v ( t ) into Lv" ( t ) + Rv' ( t ) + (l/ C ) v ( t ), and H consists of all functions of the form v ( t ) = e − bt ( c 1 + c 2 t ). Find a basis for H .
Solution Summary: The author explains that the vector space H consists of all functions of the form v(t)=e-bt
(RLC circuit) The circuit in the figure consists of a resistor (R ohms), an inductor (L henrys), a capacitor (C farads), and an initial voltage source. Let b = R/(2L), and suppose R, L, and C have been selected so that b also equals
1
/
LC
. (This is done, for instance, when the circuit is used in a voltmeter.) Let v(t) be the voltage (in volts) at time t, measured across the capacitor. It can be shown that v is in the null space H of the linear transformation that maps v(t) into Lv"(t) + Rv'(t) + (l/C)v(t), and H consists of all functions of the form v(t) = e−bt(c1 + c2t). Find a basis for H.
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
Chapter 4 Solutions
Linear Algebra and Its Applications, Books a la Carte Edition Plus MyLab Math with Pearson eText -- Access Code Card (5th Edition)
University Calculus: Early Transcendentals (4th Edition)
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