To determine To find: The value of f [ g ( 0 ) ] and g [ f ( 0 ) ] . Explanation Given: The functions are f ( x ) = 2 x − 1 and g ( x ) = 3 x + 5 . Calculation: Obtain the value of g ( 0 ) by substituting 0 for x in g ( x ) = 3 x + 5 . g ( 0 ) = 3 ( 0 ) + 5 = 0 + 5 = 5 Obtain the value of f [ g ( 0 ) ] by substituting the value of g ( 0 ) for x in f ( x ) = 2 x − 1 . f [ g ( 0 ) ] = f [ 5 ] = 2 ( 5 ) − 1 = 2 5 − 1 Thus, the required value is f [ g ( 0 ) ] = 2 5 − 1

Calculus with Applications (11th Edition)

11th Edition

ISBN: 9780321979421

Author: Margaret L. Lial, Raymond N. Greenwell, Nathan P. Ritchey

Publisher: PEARSON

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Chapter 4.3, Problem 1YT

To determine

To find: The value of f[g(0)] and g[f(0)] .

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Chapter 4.2, Problem 56E

Chapter 4.3, Problem 2YT

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Chapter 4 Solutions

Calculus with Applications (11th Edition)

Ch. 4.1 - YOUR TURN 1 find f′(t). Ch. 4.1 - YOUR TURN 2 find dy/dx. Ch. 4.1 - Prob. 3YT Ch. 4.1 - Prob. 4YT Ch. 4.1 - Prob. 5YT Ch. 4.1 - Prob. 1WE Ch. 4.1 - Prob. 2WE Ch. 4.1 - Find the derivative of each function defined as...Ch. 4.1 - Find the derivative of each function defined as...Ch. 4.1 - Find the derivative of each function defined as...

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