
Concept explainers
(a)
Find the value of sin t if sin ( − t ) = 38 by using the Trigonometric Rule.
(a)

Answer to Problem 50E
− 38
Explanation of Solution
Given: The angle sin ( − t ) = 38
Concept Used:
In Trigonometry we know that: sin (θ + 2πn ) = ± sin θ ; cos (θ + 2πn ) = ±cos θ (positive or negative) depending on the values of n and the quadrant
For any integer n and real number t = θ , the functions that behave in such a repetitive (cyclic) manner are called periodic.
Sine and Cosine functions are periodic and have a period 2π
The cosine and secant functions are even
cos ( − θ) = cos θ ; sec ( − θ) = sec θ
The sine, cosecant, tangent and cotangent functions are odd.
sin ( − θ) = − sinθ ; csc ( − θ) = − csc θ ; tan ( − θ) = − tan θ ; cot ( − θ) = − cot θ ;
Calculation:
Using the rule: sin ( − θ) = − sinθ ; csc ( − θ) = − csc θ ;
sin ( − θ) = − sinθ
Given: sin ( − t ) = 38
sin ( − t ) = − sin t = − 12sin ( − t ) = − 12
Thus the value of sin t = − 38
(b)
Find the value of csc t if sin ( − t ) = 38 by using the Trigonometric Rule
(b)

Answer to Problem 50E
− 83
Explanation of Solution
Given: The angle sin ( − t ) = 38
Concept Used:
In Trigonometry we know that: sin (θ + 2πn ) = ± sin θ ; cos (θ + 2πn ) = ±cos θ (positive or negative) depending on the values of n and the quadrant
For any integer n and real number t = θ , the functions that behave in such a repetitive (cyclic) manner are called periodic.
Sine and Cosine functions are periodic and have a period 2π
The cosine and secant functions are even
cos ( − θ) = cos θ ; sec ( − θ) = sec θ
The sine, cosecant, tangent and cotangent functions are odd.
sin ( − θ) = − sinθ ; csc ( − θ) = − csc θ ; tan ( − θ) = − tan θ ; cot ( − θ) = − cot θ ;
Calculation:
Using the rule: sin ( − θ) = − sinθ ; csc ( − θ) = − csc θ ;
csc ( − t ) = − csc t
Given: sin ( − t ) = 38
sin t = − 38csc t = 1sin t = − 138 = − 83 csc ( − t) = − 83
Thus the value of csc ( − t) = − 83
Chapter 4 Solutions
Precalculus with Limits: A Graphing Approach
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