COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG
COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG
3rd Edition
ISBN: 9780134671123
Author: Bryant
Publisher: PEARSON
Expert Solution & Answer
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Chapter 4.1, Problem 4.5PP

Explanation of Solution

Given assembly code:

long sum(long *start, long count)

start in %rdi, count in %rsi

sum:

irmovq $8, %r8

irmovq $1, %r9

xorq %rax, %rax     

andq %rsi, %rsi

jmp test

loop:

mrmovq (%rdi),%r10

addq %r10, %rax

addq %r8, %rdi

subq %r9, %rsi

test:

jne loop

ret

Data movement instructions:

  • The different instructions are been grouped as “instruction classes”.
  • The instructions in a class performs same operation but with different sizes of operand.
  • The “Mov” class denotes data movement instructions that copy data from a source location to a destination.
  • The class has 4 instructions that includes:
    • movb:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 1 byte data size.
    • movw:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 2 bytes data size.
    • movl:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 4 bytes data size.
    • movq:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 8 bytes data size.

Unary and Binary Operations:

  • The details of unary operations includes:
    • The single operand functions as both source as well as destination.
    • It can either be a memory location or a register.
    • The instruction “incq” causes 8 byte element on stack top to be incremented.
    • The instruction “decq” causes 8 byte element on stack top to be decremented.
  • The details of binary operations includes:
    • The first operand denotes the source.
    • The second operand works as both source as well as destination.
    • The first operand can either be an immediate value, memory location or register.
    • The second operand can either be a register or a memory location.

Jump Instruction:

  • The “jump” instruction causes execution to switch to an entirely new position in program.
  • The “label” indicates jump destinations in assembly code.
  • The “je” instruction denotes “jump if equal” or “jump if zero”...

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using r language
Programming Problems 9.28 Assume that a system has a 32-bit virtual address with a 4-KB page size. Write a C program that is passed a virtual address (in decimal) on the command line and have it output the page number and offset for the given address. As an example, your program would run as follows: ./addresses 19986 Your program would output: The address 19986 contains: page number = 4 offset = 3602 Writing this program will require using the appropriate data type to store 32 bits. We encourage you to use unsigned data types as well. Programming Projects Contiguous Memory Allocation In Section 9.2, we presented different algorithms for contiguous memory allo- cation. This project will involve managing a contiguous region of memory of size MAX where addresses may range from 0 ... MAX - 1. Your program must respond to four different requests: 1. Request for a contiguous block of memory 2. Release of a contiguous block of memory 3. Compact unused holes of memory into one single block 4.…
using r language

Chapter 4 Solutions

COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG

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