The reason for which the stopping potential depends on the frequency of light instead of the intensity of light.

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Chapter 40, Problem 5CQ

To determine

The reason for which the stopping potential depends on the frequency of light instead of the intensity of light.

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ՍՈՈՒ XVirginia Western Community Coll x P Course Home X + astering.pearson.com/?courseld=13289599#/ Figure y (mm) x=0x = 0.0900 m All ✓ Correct For either the time for one full cycle is 0.040 s; this is the period. Part C - ON You are told that the two points x = 0 and x = 0.0900 m are within one wavelength of each other. If the wave is moving in the +x-direction, determine the wavelength. Express your answer to two significant figures and include the appropriate units. 0 t(s) λ = Value m 0.01 0.03 0.05 0.07 Copyright © 2025 Pearson Education Inc. All rights reserved. 日 F3 F4 F5 1775 % F6 F7 B F8 Submit Previous Answers Request Answer ? × Incorrect; Try Again; 3 attempts remaining | Terms of Use | Privacy Policy | Permissions | Contact Us | Cookie Settings 28°F Clear 4 9:23 PM 1/20/2025 F9 prt sc F10 home F11 end F12 insert delete 6 7 29 & * ( 8 9 0 t = back Ο

Part C Find the height yi from which the rock was launched. Express your answer in meters to three significant figures. Learning Goal: To practice Problem-Solving Strategy 4.1 for projectile motion problems. A rock thrown with speed 12.0 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 19.0 m before hitting the ground. From what height was the rock thrown? Use the value g = 9.800 m/s2 for the free-fall acceleration. PROBLEM-SOLVING STRATEGY 4.1 Projectile motion problems MODEL: Is it reasonable to ignore air resistance? If so, use the projectile motion model. VISUALIZE: Establish a coordinate system with the x-axis horizontal and the y-axis vertical. Define symbols and identify what the problem is trying to find. For a launch at angle θ, the initial velocity components are vix=v0cosθ and viy=v0sinθ. SOLVE: The acceleration is known: ax=0 and ay=−g. Thus, the problem becomes one of…

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