Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
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ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 40, Problem 13OQ
To determine
The phenomena that clearly demonstrates the particle nature of light.
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The photoelectric equation for the kinetic energy of a photoelectron is, following Einstein, E <
hf – W, where h is Planck's constant, f is the frequency of the light, and W is the work-function.
Sodium has W = 3.2×10-19 J. When sodium is illuminated by monochromatic light of a particular
frequency, electrons are emitted with speeds up to 8 x 105 ms-1.
a) Calculate the wavelength of the light.
b) Calculate the stopping potential.
The photoelectric equation for the kinetic energy of a photoelectron is, following Einstein, E <
hf – W, where h is Planck's constant, f is the frequency of the light, and W is the work-function.
Sodium has W = 3.2 x 10-19 J. When sodium is illuminated by monochromatic light of a particular
frequency, electrons are emitted with speeds up to 8 x 105 m s-1.
a)
Calculate the wavelength of the light.
b)
Calculate the stopping potential.
The photoelectric equation for the kinetic energy of a photoelectron is, following Einstein, E <
hf – W, whereh is Planck's constant, f is the frequency of the light, and W is the work-function.
Sodium has W = 3.2×10-19 J. When sodium is illuminated by monochromatic light of a particular
frequency, electrons are emitted with speeds up to 8 x 105 ms-1.
a) Calculate the wavelength of the light.
b) Calculate the stopping potential.
Chapter 40 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 40.1 - Prob. 40.1QQCh. 40.2 - Prob. 40.2QQCh. 40.2 - Prob. 40.3QQCh. 40.2 - Prob. 40.4QQCh. 40.3 - Prob. 40.5QQCh. 40.5 - Prob. 40.6QQCh. 40.6 - Prob. 40.7QQCh. 40 - Prob. 1OQCh. 40 - Prob. 2OQCh. 40 - Prob. 3OQ
Ch. 40 - Prob. 4OQCh. 40 - Prob. 5OQCh. 40 - Prob. 6OQCh. 40 - Prob. 7OQCh. 40 - Prob. 8OQCh. 40 - Prob. 9OQCh. 40 - Prob. 10OQCh. 40 - Prob. 11OQCh. 40 - Prob. 12OQCh. 40 - Prob. 13OQCh. 40 - Prob. 14OQCh. 40 - Prob. 1CQCh. 40 - Prob. 2CQCh. 40 - Prob. 3CQCh. 40 - Prob. 4CQCh. 40 - Prob. 5CQCh. 40 - Prob. 6CQCh. 40 - Prob. 7CQCh. 40 - Prob. 8CQCh. 40 - Prob. 9CQCh. 40 - Prob. 10CQCh. 40 - Prob. 11CQCh. 40 - Prob. 12CQCh. 40 - Prob. 13CQCh. 40 - Prob. 14CQCh. 40 - Prob. 15CQCh. 40 - Prob. 16CQCh. 40 - Prob. 17CQCh. 40 - The temperature of an electric heating element is...Ch. 40 - Prob. 2PCh. 40 - Prob. 3PCh. 40 - Prob. 4PCh. 40 - Prob. 5PCh. 40 - Prob. 6PCh. 40 - Prob. 7PCh. 40 - Prob. 8PCh. 40 - Prob. 9PCh. 40 - Prob. 10PCh. 40 - Prob. 11PCh. 40 - Prob. 12PCh. 40 - Prob. 14PCh. 40 - Prob. 15PCh. 40 - Prob. 16PCh. 40 - Prob. 17PCh. 40 - Prob. 18PCh. 40 - Prob. 19PCh. 40 - Prob. 20PCh. 40 - Prob. 21PCh. 40 - Prob. 22PCh. 40 - Prob. 23PCh. 40 - Prob. 25PCh. 40 - Prob. 26PCh. 40 - Prob. 27PCh. 40 - Prob. 28PCh. 40 - Prob. 29PCh. 40 - Prob. 30PCh. 40 - Prob. 31PCh. 40 - Prob. 32PCh. 40 - Prob. 33PCh. 40 - Prob. 34PCh. 40 - Prob. 36PCh. 40 - Prob. 37PCh. 40 - Prob. 38PCh. 40 - Prob. 39PCh. 40 - Prob. 40PCh. 40 - Prob. 41PCh. 40 - Prob. 42PCh. 40 - Prob. 43PCh. 40 - Prob. 45PCh. 40 - Prob. 46PCh. 40 - Prob. 47PCh. 40 - Prob. 48PCh. 40 - Prob. 49PCh. 40 - Prob. 50PCh. 40 - Prob. 51PCh. 40 - Prob. 52PCh. 40 - Prob. 53PCh. 40 - Prob. 54PCh. 40 - Prob. 55PCh. 40 - Prob. 56PCh. 40 - Prob. 57PCh. 40 - Prob. 58PCh. 40 - Prob. 59PCh. 40 - Prob. 60APCh. 40 - Prob. 61APCh. 40 - Prob. 62APCh. 40 - Prob. 63APCh. 40 - Prob. 64APCh. 40 - Prob. 65APCh. 40 - Prob. 66APCh. 40 - Prob. 67APCh. 40 - Prob. 68APCh. 40 - Prob. 69APCh. 40 - Prob. 70APCh. 40 - Prob. 71APCh. 40 - Prob. 72CPCh. 40 - Prob. 73CPCh. 40 - Prob. 74CPCh. 40 - Prob. 75CPCh. 40 - Prob. 76CP
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- The photoelectric equation for the kinetic energy of a photoelectron is, following Einstein, E ≤hf − W, where h is Planck’s constant, f is the frequency of the light, and W is the work-function.Sodium has W = 3.2×10−19 J. When sodium is illuminated by monochromatic light of a particularfrequency, electrons are emitted with speeds up to 8 × 105 m s−1.a) Calculate the wavelength of the light.b) Calculate the stopping potential.arrow_forwardAn x-ray source generates EM radiation with a wavelength of 45.0 pm (10-12 m). h = c = qelectron = e = 1.602x10-19 C, ke = 8.99x109 N·m2/C2, What is the energy associated with this x-ray wave? What potential difference must be applied to the electrons in the x-ray tube to produce this x-ray? The air gap in the x-ray tube is 30.0 μ How much charge must be present on the plates to create this potential difference for a single electron? What is the force on a single electron when it is at 30.0 μm from the positive plate?arrow_forwardA monochromatic light source illuminates the surface of metal X. The maximum kinetic energy of electrons leaving the surface of the metal is shown in the graph above.An ammeter is connected to the standard photoelectric effect circuit to measure the photoelectric current arising from the electrons moving between the cathode and anode of the vacuum tube containing the illuminated sample. The current is found to be 12.4mA when the metal is illuminated with a wavelength of 184.2nm.What is the energy (eV) of the photons striking metal X?arrow_forward
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