Explanation a) MnCO 3 + H 2 SO 4 → MnSO 4 + H 2 O+CO 2 From the solubility rules, MnSO 4 is soluble and MnCO 3 is insoluble. The ionic equation is, MnCO 3 ( s ) + 2 H + ( a q ) +SO 4 2 − ( a q ) → Mn 2+ ( a q ) +SO 4 2 − ( a q ) + H 2 O+CO 2 ( g ) In this ionic equation, the ion SO 4 2 − is present on both sides of the equation. These are the spectator ions. Canceling these ions, we get, MnCO 3 ( s ) + 2 H + ( a q ) + SO 4 2 − ( a q ) → Mn 2+ ( a q ) + SO 4 2 − ( a q ) + H 2 O+CO 2 ( g ) Thus, the net ionic equation is, MnCO 3 ( s ) + 2 H + ( a q ) → Mn 2+ ( a q ) + H 2 O+CO 2 ( g ) So, the reaction takes place because there is the formation of water and CO 2 gas. b) Na 2 C 2 O 4 + 2 HNO 3 → 2 NaNO 3 + H 2 C 2 O 4 From the solubility rules, Na 2 C 2 O 4 and NaNO 3 are soluble

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Organometallic Compounds of s- and p- block elements

Organometallic compounds have a minimum of one bond between a metal compound and a carbon atom. Metalloid elements such as silicon, tin, and boron form organometallic compounds which can be utilized in a few commercial chemical reactions.

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Chapter 4, Problem 96RQ

Interpretation Introduction

Interpretation:

The reason for the occurrence of the given reactions is to be explained.

Concept Introduction:

In a double replacement reaction, the anion or cation of one reactant is replaced by the anion or cation of another reactant.

A net ionic equation shows a net ionic reaction.

Solubility rules determine the solubility of ions in a given neutral solution.

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Chapter 4, Problem 95RQ

Chapter 4, Problem 97RQ

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Chapter 4 Solutions

CHEMISTRY:MOLECULAR NATURE (LL)W/ACCESS

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Solution Summary: The author explains the reason for the occurrence of the given reactions in a net ionic equation.

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