Chapter 4, Problem 108RQ

Interpretation Introduction

Interpretation:

The volume of ${\text{HNO}}_3$ of given molarity, which contains $1.67\text{ g}$ of ${\text{HNO}}_3$ is to be calculated.

Concept Introduction:

Molarity is defined as the number of moles of solute present in one liter of solution and it is calculated by the expression as follows:

$\text{molarity}=\frac{\text{moles of solute}}{\text{liter of solution}}$

The unit of molarity is mol per liter.

The moles of a solute can be calculated by the formula as follows,

$\text{moles of solute}=\frac{\text{Given mass of solute}}{\text{molar mass of solute}}$

The unit of molarity is mol per liter.

Since, $\text{1000 mL is equal to 1 L}$, conversion factor for milliliter to liter is as:

$\frac{\text{1}\text{L}}{\text{1000}\text{mL}}$