Chapter 4, Problem 95E

Interpretation Introduction

Interpretation:

The given question stated that lakes that have been acidified by acid rain can be neutralized by a process called liming. In liming, limestone is added to the acidified water. The molarity of ${\text{H}}_2{\text{SO}}_4$ is $1.8\times {10}^{-5}\text{M}$ and of ${\text{HNO}}_3$ is $8.7\times {10}^{-6}\text{M}$ . The mass of limestone $\left(\text{in}\text{kg}\right)$ required to neutralize a $15.2\text{billion-liter}$ lake is to be calculated.

Concept introduction: The formula to calculate molarity is,

$M=\frac{n}{V}$

The formula to calculate number of moles is,

$n=\frac{m}{M_w}$

To determine: The mass of limestone $\left(\text{in}\text{kg}\right)$ required to neutralize a $15.2\text{billion-liter}$ lake.