EBK ESSENTIAL ORGANIC CHEMISTRY
EBK ESSENTIAL ORGANIC CHEMISTRY
3rd Edition
ISBN: 8220100659461
Author: Bruice
Publisher: PEARSON
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Chapter 4, Problem 67P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity.  Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center.  The higher the atomic number of atom, higher the priority.  If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority.  If the arrow points clockwise direction, then the compound has R configuration.  If the arrow points counterclockwise direction, then the compound has S configuration.  If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

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The stereoisomer of cholesterol found in nature is shown here.a. How many asymmetric centers does cholesterol have? b. What is the maximum number of stereoisomers that cholesterol can have?
The stereoisomer of cholesterol found in nature is shown here.a. How many asymmetric centers does cholesterol have? b. What is the maximum number of stereoisomers that cholesterol can have?
9.a. Circle all the appropriate terms. t-Bu The two molecules drawn above are enantiomers optically active enantiomers superimposable 9.b. Circle all the appropriate terms. diastereomers not optically active H optically active Bull.... H₂CH... Br -CH3 The two molecules drawn above are Me H diastereomers not optically active superimposable Me chiral meso not superimposable H3C- H ....... chiral meso H ...III\CH3 Br not superimposable Cl achiral -t-Bu identical achiral identical 3

Chapter 4 Solutions

EBK ESSENTIAL ORGANIC CHEMISTRY

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