Explanation Given information: The statement “The function P = 1000 ( 1 + 2 e − 3 t ) has an inflection point when P = 500. ” For positive constants L, C, and k, a logistic function has the form P = f ( t ) = L 1 + C e − k t . The parameter L of the logistic function is the value at which P levels off, where P = L 1 + C e − k t . This value L is called the carrying capacity and represents the largest population an environment can support.One way to estimate the carrying capacity is to find the inflection point

6th Edition

ISBN: 9781119267874

Author: Hughes-Hallett

Publisher: WILEY

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Differential Equations

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Chapter 4, Problem 64SYU

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Chapter 4, Problem 63SYU

Chapter 4, Problem 65SYU

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(12 points) Let E={(x, y, z)|x²+ y² + z² ≤ 4, x, y, z > 0}. (a) (4 points) Describe the region E using spherical coordinates, that is, find p, 0, and such that (x, y, z) (psin cos 0, psin sin 0, p cos) € E. (b) (8 points) Calculate the integral E xyz dV using spherical coordinates.

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(14 points) Let f: R3 R and T: R3. →R³ be defined by f(x, y, z) = ln(x²+ y²+2²), T(p, 0,4)=(psin cos 0, psin sin, pcos). (a) (4 points) Write out the composition g(p, 0, 4) = (foT)(p,, ) explicitly. Then calculate the gradient Vg directly, i.e. without using the chain rule. (b) (4 points) Calculate the gradient Vf(x, y, z) where (x, y, z) = T(p, 0,4). (c) (6 points) Calculate the derivative matrix DT(p, 0, p). Then use the Chain Rule to calculate Vg(r,0,4).

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To indicate: Whether the statement is true or false.

Solution Summary: The author explains that a logistic function has the form P=f(t)=L1+Ce-k