Explanation Given information: f ( x ) = x e a x has a critical point at x = 3. Definition used: For any function f , a point p in the domain of f where f ' ( p ) = 0 or f ' ( p ) is undefined is called a critical point of the function. Calculation: f ( x ) = x e a x (Given) Differentiating with respect to ‘x’, we get f ' ( x ) = e a x + a x e a x = e a x ( 1 + a x ) f ( x )

6th Edition

ISBN: 9781119267874

Author: Hughes-Hallett

Publisher: WILEY

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Question

Chapter 4.1, Problem 50P

To determine

To find:

The value of a so that f(x)=xeax has a critical point at x=3.

Expert Solution & Answer

Chapter 4 Solutions

APPLIED CALCULUS-WILEYPLUS

Ch. 4.1 - Prob. 1P Ch. 4.1 - Prob. 2P Ch. 4.1 - Prob. 3P Ch. 4.1 - Prob. 4P Ch. 4.1 - Prob. 5P Ch. 4.1 - Prob. 6P Ch. 4.1 - Prob. 7P Ch. 4.1 - Prob. 8P Ch. 4.1 - Prob. 9P Ch. 4.1 - Prob. 10P

Ch. 4.1 - Prob. 11P Ch. 4.1 - Prob. 12P Ch. 4.1 - Prob. 13P Ch. 4.1 - Prob. 14P Ch. 4.1 - Prob. 15P Ch. 4.1 - Prob. 16P Ch. 4.1 - Prob. 17P Ch. 4.1 - Prob. 18P Ch. 4.1 - Prob. 19P Ch. 4.1 - Prob. 20P Ch. 4.1 - Prob. 21P Ch. 4.1 - Prob. 22P Ch. 4.1 - Prob. 23P Ch. 4.1 - Prob. 24P Ch. 4.1 - Prob. 25P Ch. 4.1 - Prob. 26P Ch. 4.1 - Prob. 27P Ch. 4.1 - Prob. 28P Ch. 4.1 - Prob. 29P Ch. 4.1 - Prob. 30P Ch. 4.1 - Prob. 31P Ch. 4.1 - Prob. 32P Ch. 4.1 - Prob. 33P Ch. 4.1 - Prob. 34P Ch. 4.1 - Prob. 35P Ch. 4.1 - Prob. 36P Ch. 4.1 - Prob. 37P Ch. 4.1 - Prob. 38P Ch. 4.1 - Prob. 39P Ch. 4.1 - Prob. 40P Ch. 4.1 - Prob. 41P Ch. 4.1 - Prob. 42P Ch. 4.1 - Prob. 43P Ch. 4.1 - Prob. 44P Ch. 4.1 - Prob. 45P Ch. 4.1 - Prob. 46P Ch. 4.1 - Prob. 47P Ch. 4.1 - Prob. 48P Ch. 4.1 - Prob. 49P Ch. 4.1 - Prob. 50P Ch. 4.1 - Prob. 51P Ch. 4.1 - Prob. 52P Ch. 4.1 - Prob. 53P Ch. 4.1 - Prob. 54P Ch. 4.1 - Prob. 55P Ch. 4.1 - Prob. 56P Ch. 4.1 - Prob. 57P Ch. 4.1 - Prob. 58P Ch. 4.2 - Prob. 1P Ch. 4.2 - Prob. 2P Ch. 4.2 - 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The value of a so that f ( x ) = x e a x has a critical point at x = 3.

Solution Summary: The author explains that the value of a is f(x)=xeax, which is critical to the function.

Concept explainers

Videos

To find:

The value of a so that f(x)=xeax has a critical point at x=3.

Chapter 4 Solutions

The value of a so that f ( x ) = x e a x has a critical point at x = 3.

Solution Summary: The author explains that the value of a is f(x)=xeax, which is critical to the function.

Concept explainers

Videos

To find: The value of a so that f(x)=xeax has a critical point at x=3.

Chapter 4 Solutions

To find:

The value of a so that f(x)=xeax has a critical point at x=3.