A centripetal-acceleration addict rides in uniform circular motion with radius r = 3.00 m. At one instant his acceleration is a → = ( 6.00 m/s 2 ) i ^ + ( − 4. 00 m/s 2 ) j ^ . At that instant, what are the values of (a) v → · a → and (b) r → × a → ?
A centripetal-acceleration addict rides in uniform circular motion with radius r = 3.00 m. At one instant his acceleration is a → = ( 6.00 m/s 2 ) i ^ + ( − 4. 00 m/s 2 ) j ^ . At that instant, what are the values of (a) v → · a → and (b) r → × a → ?
A centripetal-acceleration addict rides in uniform circular motion with radius r = 3.00 m. At one instant his acceleration is
a
→
=
(
6.00
m/s
2
)
i
^
+ (
−
4.
00 m/s
2
)
j
^
. At that instant, what are the values of (a)
v
→
·
a
→
and (b)
r
→
×
a
→
?
A cab driver heads south with a steady speed of v₁ = 20.0 m/s for t₁ = 3.00 min, then makes a right turn and travels at v₂ = 25.0 m/s for t₂ = 2.80 min, and then drives northwest at v3 = 30.0 m/s for t3 = 1.00 min. For this 6.80-min trip, calculate the following.
Assume +x is in the eastward direction.
(a) total vector displacement (Enter the magnitude in m and the direction in degrees south of west.)
magnitude
direction
For each straight-line movement, model the car as a particle under constant velocity, and draw a diagram of the displacements, labeling the distances and angles. Let the starting point be the origin of your coordinate system. Use the relationship
speed = distance/time to find the distances traveled during each segment. Write the displacement vector, and calculate its magnitude and direction. Don't forget to convert min to s! m
Model the car as a particle under constant velocity, and draw a diagram of the displacements, labeling the distances and angles. Let the…
î
A proton is projected in the positive x direction into a region of uniform electric field E = (-5.50 x 105) i N/C at t = 0. The
proton travels 7.20 cm as it comes to rest.
(a) Determine the acceleration of the proton.
magnitude 5.27e13
direction -X
m/s²
(b) Determine the initial speed of the proton.
8.71e-6
magnitude The electric field is constant, so the force is constant, which means the acceleration will be constant.
m/s
direction +X
(c) Determine the time interval over which the proton comes to rest.
1.65e-7
Review you equations for constant accelerated motion. s
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μC, and
L = 0.750 m.)
y
7.00 με
60.0°
L
9
-4.00 μC
x
(a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges.
112
Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors.
KN/CI + 64
×
Think carefully about the direction of the field due to the 7.00-μC charge. KN/Cĵ
(b) Use your answer to part (a) to determine the force on charge q.
240.0
If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN
Î + 194.0
×
If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
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