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A hot liquid flows along a V-groove in a solid whose top and side surfaces are well insulated and whose bottom surface is in contact with a coolant.
Accordingly. the V-groove surface is at a temperature
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Chapter 4 Solutions
Fundamentals of Heat and Mass Transfer
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- An unpressurized cylindrical tank with a 100-foot diameter holds a 40-foot column of water. What is total force acting against the bottom of the tank?arrow_forward7. In the following problems check to see if the set S is a vector subspace of the corresponding R. If it is not, explain why not. If it is, then find a basis and the dimension. (a) S = (b) S = {[],+,"} X1 x12x2 = x3 CR³ {[1], 4+4 = 1} CR³ X2arrow_forwardAAA Show laplace transform on 1; (+) to L (y(+)) : SY(s) = x (0) Y(s) = £ [lx (+)] = 5 x(+) · est de 2 -St L [ y (^) ] = So KG) et de D 2 D D AA Y(A) → Y(s) Ŷ (+) → s Y(s) -yarrow_forward
- 1) In each of the following scenarios, based on the plane of impact (shown with an (n, t)) and the motion of mass 1, draw the direction of motion of mass 2 after the impact. Note that in all scenarios, mass 2 is initially at rest. What can you say about the nature of the motion of mass 2 regardless of the scenario? m1 15 <+ m2 2) y "L χ m1 m2 m1 בז m2 Farrow_forward8. In the following check to see if the set S is a vector subspace of the corresponding Rn. If it is not, explain why not. If it is, then find a basis and the dimension. X1 (a) S = X2 {[2], n ≤ n } c X1 X2 CR² X1 (b) S X2 = X3 X4 x1 + x2 x3 = 0arrow_forward2) Suppose that two unequal masses m₁ and m₂ are moving with initial velocities V₁ and V₂, respectively. The masses hit each other and have a coefficient of restitution e. After the impact, mass 1 and 2 head to their respective gaps at angles a and ẞ, respectively. Derive expressions for each of the angles in terms of the initial velocities and the coefficient of restitution. m1 m2 8 m1 ↑ บา m2 ñ Вarrow_forward
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- The state of stress at a point is σ = -4.00 kpsi, σy = 16.00 kpsi, σ = -14.00 kpsi, Try = 11.00 kpsi, Tyz = 8.000 kpsi, and T = -14.00 kpsi. Determine the principal stresses. The principal normal stress σ₁ is determined to be [ The principal normal stress σ2 is determined to be [ The principal normal stress σ3 is determined to be kpsi. kpsi. The principal shear stress 71/2 is determined to be [ The principal shear stress 7½ is determined to be [ The principal shear stress T₁/, is determined to be [ kpsi. kpsi. kpsi. kpsi.arrow_forwardRepeat Problem 28, except using a shaft that is rotatingand transmitting a torque of 150 N * m from the left bearing to the middle of the shaft. Also, there is a profile keyseat at the middle under the load. (I want to understand this problem)arrow_forwardProb 2. The material distorts into the dashed position shown. Determine the average normal strains &x, Ey and the shear strain Yxy at A, and the average normal strain along line BE. 50 mm B 200 mm 15 mm 30 mm D ΕΙ 50 mm x A 150 mm Farrow_forward
- Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning
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