ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
7th Edition
ISBN: 9781319399849
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 4, Problem 4H.1BST
(a)
Interpretation Introduction
Interpretation:
The most ordered allotrope of tin and the sign of the entropy change have to be given.
(b)
Interpretation Introduction
Interpretation:
The most ordered allotrope of carbon and the sign of the entropy change have to be given.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Bromine monofluoride (BrF) disproportionates to bromine gas and bromine tri- and pentafluorides. Use the following to find ΔH°rxn for the decomposition of BrF to its elements 3BrF(g) →Br₂(g)+BrF₃(l) ΔH°rxn=-125.3 kJ 5BrF(g) →2Br₂(g)+BrF₅(l) ΔH°rxn=-166.1 kJ BrF₃(l)+F₂(g) →BrF₅(l) ΔH°rxn=-158.0 kJ
In a study of glass etching, a chemist examines the reaction between sand
(Sio2) and hydrogen fluoride at 150°c (given by the reaction below). Predict
the effect on [SIF4] when (a) H2O(g) is removed; (b) some liquid water is
added; (c) HF is removed; (d) some sand is removed.
SiO2(s) + 4HF(g)
= SiF,(g) + 2H2O(g)
O (a) decreases; (b) decreases ; (c) decreases ; (d) no effect
O (a) increases; (b) decreases ; (c) decreases ; (d) no effect
O (a) increases; (b) increases; (c) decreases; (d) no effect
(a) no effect; (b) decreases; (c) decreases ; (d) no effect
The standard enthalpy change of combustion of graphite and diamond are −393.5 kJ mol−1 and −395.4 kJ mol−1 respectively.
(a) By drawing a suitable energy cycle, calculate the standard enthalpy change of formation of graphite from diamond.
(b) Hence explain which, diamond or graphite, is the more stable form of carbon.
Chapter 4 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
Ch. 4 - Prob. 4A.1ASTCh. 4 - Prob. 4A.1BSTCh. 4 - Prob. 4A.2ASTCh. 4 - Prob. 4A.2BSTCh. 4 - Prob. 4A.3ASTCh. 4 - Prob. 4A.3BSTCh. 4 - Prob. 4A.4ASTCh. 4 - Prob. 4A.4BSTCh. 4 - Prob. 4A.1ECh. 4 - Prob. 4A.2E
Ch. 4 - Prob. 4A.3ECh. 4 - Prob. 4A.4ECh. 4 - Prob. 4A.5ECh. 4 - Prob. 4A.6ECh. 4 - Prob. 4A.7ECh. 4 - Prob. 4A.8ECh. 4 - Prob. 4A.9ECh. 4 - Prob. 4A.10ECh. 4 - Prob. 4A.11ECh. 4 - Prob. 4A.12ECh. 4 - Prob. 4A.13ECh. 4 - Prob. 4A.14ECh. 4 - Prob. 4B.1ASTCh. 4 - Prob. 4B.1BSTCh. 4 - Prob. 4B.2ASTCh. 4 - Prob. 4B.2BSTCh. 4 - Prob. 4B.3ASTCh. 4 - Prob. 4B.3BSTCh. 4 - Prob. 4B.1ECh. 4 - Prob. 4B.2ECh. 4 - Prob. 4B.3ECh. 4 - Prob. 4B.4ECh. 4 - Prob. 4B.5ECh. 4 - Prob. 4B.6ECh. 4 - Prob. 4B.7ECh. 4 - Prob. 4B.8ECh. 4 - Prob. 4B.9ECh. 4 - Prob. 4B.10ECh. 4 - Prob. 4B.11ECh. 4 - Prob. 4B.12ECh. 4 - Prob. 4B.13ECh. 4 - Prob. 4B.14ECh. 4 - Prob. 4B.15ECh. 4 - Prob. 4B.16ECh. 4 - Prob. 4C.1ASTCh. 4 - Prob. 4C.1BSTCh. 4 - Prob. 4C.2ASTCh. 4 - Prob. 4C.2BSTCh. 4 - Prob. 4C.3ASTCh. 4 - Prob. 4C.3BSTCh. 4 - Prob. 4C.4ASTCh. 4 - Prob. 4C.4BSTCh. 4 - Prob. 4C.1ECh. 4 - Prob. 4C.2ECh. 4 - Prob. 4C.3ECh. 4 - Prob. 4C.4ECh. 4 - Prob. 4C.5ECh. 4 - Prob. 4C.6ECh. 4 - Prob. 4C.7ECh. 4 - Prob. 4C.8ECh. 4 - Prob. 4C.9ECh. 4 - Prob. 4C.10ECh. 4 - Prob. 4C.11ECh. 4 - Prob. 4C.12ECh. 4 - Prob. 4C.13ECh. 4 - Prob. 4C.14ECh. 4 - Prob. 4C.15ECh. 4 - Prob. 4C.16ECh. 4 - Prob. 4D.1ASTCh. 4 - Prob. 4D.1BSTCh. 4 - Prob. 4D.2ASTCh. 4 - Prob. 4D.2BSTCh. 4 - Prob. 4D.3ASTCh. 4 - Prob. 4D.3BSTCh. 4 - Prob. 4D.4ASTCh. 4 - Prob. 4D.4BSTCh. 4 - Prob. 4D.5ASTCh. 4 - Prob. 4D.5BSTCh. 4 - Prob. 4D.6ASTCh. 4 - Prob. 4D.6BSTCh. 4 - Prob. 4D.7ASTCh. 4 - Prob. 4D.7BSTCh. 4 - Prob. 4D.1ECh. 4 - Prob. 4D.2ECh. 4 - Prob. 4D.3ECh. 4 - Prob. 4D.4ECh. 4 - Prob. 4D.5ECh. 4 - Prob. 4D.6ECh. 4 - Prob. 4D.7ECh. 4 - Prob. 4D.8ECh. 4 - Prob. 4D.10ECh. 4 - Prob. 4D.11ECh. 4 - Prob. 4D.13ECh. 4 - Prob. 4D.14ECh. 4 - Prob. 4D.15ECh. 4 - Prob. 4D.16ECh. 4 - Prob. 4D.17ECh. 4 - Prob. 4D.18ECh. 4 - Prob. 4D.19ECh. 4 - Prob. 4D.20ECh. 4 - Prob. 4D.21ECh. 4 - Prob. 4D.22ECh. 4 - Prob. 4D.23ECh. 4 - Prob. 4D.24ECh. 4 - Prob. 4D.25ECh. 4 - Prob. 4D.26ECh. 4 - Prob. 4D.29ECh. 4 - Prob. 4D.30ECh. 4 - Prob. 4E.1ASTCh. 4 - Prob. 4E.1BSTCh. 4 - Prob. 4E.2ASTCh. 4 - Prob. 4E.2BSTCh. 4 - Prob. 4E.5ECh. 4 - Prob. 4E.6ECh. 4 - Prob. 4E.7ECh. 4 - Prob. 4E.8ECh. 4 - Prob. 4E.9ECh. 4 - Prob. 4E.10ECh. 4 - Prob. 4F.1ASTCh. 4 - Prob. 4F.1BSTCh. 4 - Prob. 4F.2ASTCh. 4 - Prob. 4F.2BSTCh. 4 - Prob. 4F.3ASTCh. 4 - Prob. 4F.3BSTCh. 4 - Prob. 4F.4ASTCh. 4 - Prob. 4F.4BSTCh. 4 - Prob. 4F.5ASTCh. 4 - Prob. 4F.5BSTCh. 4 - Prob. 4F.6ASTCh. 4 - Prob. 4F.6BSTCh. 4 - Prob. 4F.7ASTCh. 4 - Prob. 4F.7BSTCh. 4 - Prob. 4F.8ASTCh. 4 - Prob. 4F.8BSTCh. 4 - Prob. 4F.9ASTCh. 4 - Prob. 4F.9BSTCh. 4 - Prob. 4F.1ECh. 4 - Prob. 4F.2ECh. 4 - Prob. 4F.3ECh. 4 - Prob. 4F.4ECh. 4 - Prob. 4F.5ECh. 4 - Prob. 4F.6ECh. 4 - Prob. 4F.7ECh. 4 - Prob. 4F.9ECh. 4 - Prob. 4F.10ECh. 4 - Prob. 4F.11ECh. 4 - Prob. 4F.12ECh. 4 - Prob. 4F.13ECh. 4 - Prob. 4F.14ECh. 4 - Prob. 4F.15ECh. 4 - Prob. 4F.16ECh. 4 - Prob. 4F.17ECh. 4 - Prob. 4G.1ASTCh. 4 - Prob. 4G.1BSTCh. 4 - Prob. 4G.2ASTCh. 4 - Prob. 4G.2BSTCh. 4 - Prob. 4G.1ECh. 4 - Prob. 4G.2ECh. 4 - Prob. 4G.3ECh. 4 - Prob. 4G.5ECh. 4 - Prob. 4G.7ECh. 4 - Prob. 4G.8ECh. 4 - Prob. 4G.9ECh. 4 - Prob. 4G.10ECh. 4 - Prob. 4H.1ASTCh. 4 - Prob. 4H.1BSTCh. 4 - Prob. 4H.2ASTCh. 4 - Prob. 4H.2BSTCh. 4 - Prob. 4H.1ECh. 4 - Prob. 4H.2ECh. 4 - Prob. 4H.3ECh. 4 - Prob. 4H.4ECh. 4 - Prob. 4H.5ECh. 4 - Prob. 4H.6ECh. 4 - Prob. 4H.7ECh. 4 - Prob. 4H.8ECh. 4 - Prob. 4H.9ECh. 4 - Prob. 4H.10ECh. 4 - Prob. 4H.11ECh. 4 - Prob. 4I.1ASTCh. 4 - Prob. 4I.1BSTCh. 4 - Prob. 4I.2ASTCh. 4 - Prob. 4I.2BSTCh. 4 - Prob. 4I.3ASTCh. 4 - Prob. 4I.3BSTCh. 4 - Prob. 4I.4ASTCh. 4 - Prob. 4I.4BSTCh. 4 - Prob. 4I.1ECh. 4 - Prob. 4I.2ECh. 4 - Prob. 4I.3ECh. 4 - Prob. 4I.4ECh. 4 - Prob. 4I.5ECh. 4 - Prob. 4I.6ECh. 4 - Prob. 4I.7ECh. 4 - Prob. 4I.8ECh. 4 - Prob. 4I.9ECh. 4 - Prob. 4I.10ECh. 4 - Prob. 4I.11ECh. 4 - Prob. 4I.12ECh. 4 - Prob. 4J.1ASTCh. 4 - Prob. 4J.1BSTCh. 4 - Prob. 4J.2ASTCh. 4 - Prob. 4J.2BSTCh. 4 - Prob. 4J.3ASTCh. 4 - Prob. 4J.3BSTCh. 4 - Prob. 4J.4ASTCh. 4 - Prob. 4J.4BSTCh. 4 - Prob. 4J.5ASTCh. 4 - Prob. 4J.5BSTCh. 4 - Prob. 4J.6ASTCh. 4 - Prob. 4J.6BSTCh. 4 - Prob. 4J.1ECh. 4 - Prob. 4J.2ECh. 4 - Prob. 4J.3ECh. 4 - Prob. 4J.4ECh. 4 - Prob. 4J.5ECh. 4 - Prob. 4J.6ECh. 4 - Prob. 4J.7ECh. 4 - Prob. 4J.8ECh. 4 - Prob. 4J.9ECh. 4 - Prob. 4J.11ECh. 4 - Prob. 4J.12ECh. 4 - Prob. 4J.13ECh. 4 - Prob. 4J.14ECh. 4 - Prob. 4J.15ECh. 4 - Prob. 4J.16ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.16ECh. 4 - Prob. 4.19ECh. 4 - Prob. 4.20ECh. 4 - Prob. 4.21ECh. 4 - Prob. 4.23ECh. 4 - Prob. 4.25ECh. 4 - Prob. 4.27ECh. 4 - Prob. 4.28ECh. 4 - Prob. 4.29ECh. 4 - Prob. 4.30ECh. 4 - Prob. 4.31ECh. 4 - Prob. 4.32ECh. 4 - Prob. 4.33ECh. 4 - Prob. 4.34ECh. 4 - Prob. 4.35ECh. 4 - Prob. 4.36ECh. 4 - Prob. 4.37ECh. 4 - Prob. 4.39ECh. 4 - Prob. 4.40ECh. 4 - Prob. 4.41ECh. 4 - Prob. 4.45ECh. 4 - Prob. 4.46ECh. 4 - Prob. 4.48ECh. 4 - Prob. 4.49ECh. 4 - Prob. 4.53ECh. 4 - Prob. 4.57ECh. 4 - Prob. 4.59E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Data are given in Appendix 1 for white phosphorus, P4(s). P4(g) has the following thermodynamic values: Hf=58.9kJ/mol , S=280.0J/kmol . What is the temperature at which white phosphorus sublimes at 1 atm pressure?arrow_forwardUse the appropriate tables to calculate H for (a) the reaction between copper(II) oxide and carbon monoxide to give copper metal and carbon dioxide. (b) the decomposition of one mole of methyl alcohol (CH3OH) to methane and oxygen gases.arrow_forwardCalcium carbide, CaC2, is manufactured by reducing lime with carbon at high temperature. (The carbide is used in turn to make acetylene, an industrially important organic chemical.) Is the reaction endothermic or exothermic?arrow_forward
- Boron nitride (BN) has a structure similar to graphite, but is a white insulator rather than a black conductor. It is synthesized by heating diboron trioxide with ammonia at about 1000°C. (a) Write a balanced equation for the formation of BN; water forms also.(b) Calculate ΔH°rxn for the production of BN (ΔH°f of BN is -254 kJ/mol).(c) Boron is obtained from the mineral borax, Na₂B₄O₇.10H₂O.How much borax is needed to produce 1.0 kg of BN, assuming 72% yield?arrow_forward73. Given the following data Ca(s) + 2C(graphite) Ca(s) + ¿O,(g) CaO(s) + H,O(1) C,H,(2) + 0,(g) Clgraphite) + O,(g) CaC,(s) ΔΗ--62.8 k → CaO(s) AH = -635.5 kJ Ca(OH), (aq) AH = -653.1 kJ 2CO,(g) + H,O(1) AH = -1300. kJ CO,(g) AH = -393.5 kJ calculate AH the reaction CaC,(s) + 2H,O(1) → Ca(OH),(aq) + C,H¿(g) IS ONIAarrow_forwardWhat is the average bond energy in CO2? CO2(g) ΔH°f, = –393.5 kJ mol–1 CO(g) ΔH°f, = –110.5 kJ mol–1 C(g) ΔH°f, = +715 kJ mol–1 CO32–(aq) ΔH°f, = –676.3 kJ mol–1 O(g) ΔH°f, = +249.0 kJ mol–1 Question 5 options: 207 kJ mol–1 1607 kJ mol–1 804 kJ mol–1arrow_forward
- Hydrogen peroxide can be prepared in several ways. One method is the reaction between hydrogen and oxygen, another method is the reaction between water and oxygen. Calculate the ΔGrxn∘ of each reaction using values from the table of thermodynamic properties. (1)H2(g)+O2(g)↽−−⇀H2O2(l) Δ?∘rxn= kJ⋅mo^l−1 (2)H2O(l)+12O2(g)↽−−⇀H2O2(l)arrow_forward(ii) The industrial process for producing sulphuric acid, H2SO4, from elemental sulphur has three steps, using the information below; (a) identify the three steps, and describe the nature of each step (in one phrase); (b) write an equation for the overall reaction. (c) using the data given below, calculate the enthalpy change for the overall reaction. S(s) + O2(g) SO-(g) A;H° = -296.8 kJ 2S0:(g) 2SO2(g) + O2(9) A;H° = -198.2 kJ SO((g) + H2O(1) H2SO4() A;H° = -227.7 kJarrow_forward(b) What is the first law of thermodynamic? Define the Hess law. Given the following data; 2CIF(g) + 0,(g) CI,0(g) + F,O(g) AH = 167.4 kJ AH = 341.4 kJ SH = -43,4 kJ 2CIF,(g) + 20,(g) → CĻ0(g) + 3F,O(g) 2F,(2) + O(8) → 2F,O(g) calculate AH for the reaction CIF(g) + F(8) CIF,(g)arrow_forward
- Assuming that neither standard enthalpy changes of formations (∆Hof) nor standard molar entropies (So) depend upon temperature, estimate using the Table of Thermodynamic Data : (a) the standard Gibbs free energy change for the reaction that forms rhombic sulfur at 600 K, and (b) the temperature (in oC) at which reaction will stop formation of products: 2H2S(g) + SO2(g) → 3S(rhombic, s) + 2H2O(g) Round off your answers to the nearest integer. Report the temperature in oC. and enter them with correct units: (a)∆Gorxn = (b) T =arrow_forwardCalculate the standard molar enthalpy of formation of NO(g) from the following data: (A) N₂(g)+20,-2NO(g) (B) 2NO(g)+0,-2NO,(g) AH=66.4kJ AH° -114.1kJarrow_forwardUse the data in Thermodynamic Properties to determine ΔH° for each of the following reactions.Please use the values in the Thermodynamic Properties to determine the expected number of significant figures. (a) Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) kJ(b) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) kJ(c) 2 Ag+(aq) + Pb(s) → 2 Ag(s) + Pb2+(aq) kJ(d) CH3COOH(l) + 2 O2(g) → 2 CO2(g) + 2 H2O(l) kJarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY